1. If you draw squares on the two shorter sides…
Pythagoras’ theorem only works on right – angled triangles
… and find their area.
Area A
Area B

2. Area C
Area A
Area A + Area B = Area C
The sum of their areas equals the area of the square on the longest side!
Area B

3. Find the area of the smaller squares
Find the length of x.
Find the area of the smaller squares x
9cm2
3cm
4cm
16cm2

4. What will the length x be? 9cm2
Find the length of x.
25cm2 x
What will the length x be?
9cm2
3cm
add to find the area of the large square.
x = 25 = 5cm
4cm
16cm2

5. Find the length of x. x x2 = 82 + 62 x2 = 64 + 36 x2 = 100
6cm
x2 =
8cm
x2 = 100
x = 100 = 10

6. Find the length of x. x x2 = 92 + 72 x2 = 81 + 49 x2 = 130
7cm
x2 =
9cm
x2 = 130
x = 130 = 11.4

7. This time we need to find the area of one of the smaller squares …
Find the length of x.
This time we need to find the area of one of the smaller squares …
… so we need to subtract!
12cm
x2 = x
x2 =
8cm
x2 = 80
x = 80 = 8.9