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(c) McGraw Hill Ryerson 2007 Chemical reactions result in chemical changes. –Chemical changes occur when new substances are created. –The original substance(s),

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Presentation on theme: "(c) McGraw Hill Ryerson 2007 Chemical reactions result in chemical changes. –Chemical changes occur when new substances are created. –The original substance(s),"— Presentation transcript:

1 (c) McGraw Hill Ryerson 2007 Chemical reactions result in chemical changes. –Chemical changes occur when new substances are created. –The original substance(s), called reactants, change into new substance(s) called products. See pages 202 - 203

2 (c) McGraw Hill Ryerson 2007 See pages 202 - 203

3 (c) McGraw Hill Ryerson 2007 Chemical reactions can be written in different ways. –A word equation: Nitrogen monoxide + oxygen  nitrogen dioxide –A symbolic equation: 2 gg 2 g2NO (g) + O 2(g)  2NO 2(g) STATE OF MATTER - Letters indicate the state of each compound. (aq) = aqueous/dissolved in water (s) = solid ( ) = liquid (g) = gas COEFFICIENTS - Indicates how many of each molecule there is. -Ie: there are 2 molecules of NO.

4 (c) McGraw Hill Ryerson 2007 When a chemical reaction occurs, new compounds are created, BUT… –No new matter is created or destroyed rearrangedchange partners –No new matter is created or destroyed; atoms are just rearranged as the atoms change partners to form new compounds. 3 –If there are 3 atoms of oxygen in the reactants, there MUST be 3 atoms of oxygen in the products. –Number of each atom in reactants = number of each atom in products. The law of conservation of mass: –Mass of reactants = mass of products If you could collect and measure all of the exhaust from this car, you would find that mass of reactants (gas + O 2 ) = mass of products (exhaust).

5 balanced chemical equation coefficientsA balanced chemical equation shows all atoms and the coefficients tells us how many molecules (and atoms) there are. ensures number of each atom same on both sides –Balancing ensures that the number of each atom is the same on both sides of the reaction arrow. 42 4K + O 2  2K 2 O K K K K K K K K K K K K K K K K OO O O

6 (c) McGraw Hill Ryerson 2007 Skeleton equation:CH 4 + O 2  H 2 O + CO 2 11 Carbon = 1Carbon = 1 42 Hydrogen = 4Hydrogen = 2 23 Oxygen = 2Oxygen = 3 22 11 Balanced equation:CH 4 + 2O 2  2H 2 O + CO 2 Carbon = 1Carbon = 1 44 Hydrogen = 4Hydrogen = 4 44 Oxygen = 4Oxygen = 4 The same number of atoms must be on each side. See Page 207

7 Balancing Equations ReactantsProducts H22 hydrogen + oxygen  water O 2 O 2  H2OH2OH2OH2O H 2 H 2 +O21

8 Balancing Equations H 2 + O 2  H 2 O 2 ReactantsProducts H22 O22 hydrogen + oxygen  hydrogen peroxide X YOU CANNOT CHANGE THE SUBSCRIPTS

9 Balancing Equations H 2 + O 2  H 2 O ReactantsProducts H22 O21 hydrogen + oxygen  water 2

10 Balancing Equations H 2 + O 2  H 2 O ReactantsProducts H24 O22 hydrogen + oxygen  water 2

11 Balancing Equations 2 2 H 2 + O 2  H 2 O ReactantsProducts H44 O22 hydrogen + oxygen  water 2 (g) (l)


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