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Parametric Surfaces and their Area Part I
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Parametric Surfaces Recall: A space curve is described by a vector function of one variable, r(t) As t varies in the interval [π,π], the head of the position vector π« π‘ = π₯ π‘ ,π¦ π‘ ,π§(π‘) traces the space curve C. Now suppose x, y, z depend on two parameters u, v: As the point (π’,π£) moves around D, the head of the vector π«(π’,π£) traces out a surface in 3-D. A vector function of two parameters describes a surface.
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Parametric surfaces β Example 1
Identify the parametric surface Letβs try to find a cartesian equation for the surface. We have: π₯ 2 + π¦ 2 = (π’ cos π£ ) 2 + (π’ sin π£ ) 2 = π’ 2 ( cos 2 π£+ sin 2 π£)= π’ 2 =π§ Thus the cartesian equation of the surface is π§= π₯ 2 + π¦ 2 , 0β€π§β€9, which we recognize as the part of a paraboloid over the disk π₯ 2 + π¦ 2 β€9.
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Parametric surfaces - Gridlines
If we fix one parameter, we get curves on the surface called gridlines. Example 2: Consider the paraboloid Let π£= π£ 0 = π 2 , then π₯=π’ cos π 2 =0, π¦=π’ sin π 2 =π’, π§= π’ 2 Gridline: segment of the parabola π§= π¦ 2 in the plane π₯=0 (0 β€ y β€ 3) Let π£= π£ 0 =π, then π₯=π’ cos π=βπ’, π¦=π’ sin π, π§= π’ 2 Gridline: segment of the parabola π§= π₯ 2 in the plane π¦=0 (β3 β€ x β€ 0) Lines of the form v = v0 in the domain D are mapped into gridlines (segments of parabolas) of the surface.
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Parametric surfaces β Example 2 continued
If we fix u = u0, then The gridlines are the circles on the horizontal planes Lines of the form u = u0 in the domain D are mapped into gridlines (circles) of the surface. The paraboloid with several gridlines:
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Parametric surfaces β Example 3
Identify the parametric surface Since π₯ 2 + π§ 2 = cos 2 π+ sin 2 π= 1, the surface is the circular cylinder π₯ 2 + π§ 2 =1 for β2β€π¦β€2. The gridlines are lines and circles. If we fix π= π 0 , we obtain a line parallel to the y-axis: If we fix π¦= π¦ 0 , we obtain the circle π₯ 2 + π§ 2 =1 in the plane π¦= π¦ 0 The cylinder with several gridlines:
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Parametric surfaces β Example 4
Parameterize the surface π₯ 2 + π¦ 2 + π§ 2 =4. The surface is a sphere, thus we can use spherical coordinates. Here Ο equals the radius of the sphere: π=2 . r is a function of ΞΈ and π only: Gridlines: π= π 0 : meridians (semicircles at constant latitude). π= π 0 : circles parallel to the π₯π¦-plane
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Parametric surfaces - Example 5
Parameterize the part of the sphere π₯ 2 + π¦ 2 + π§ 2 =4 that lies between the planes π§=β1 and π§=1. We can use the same r as in the previous example: However, the domain D will be different. Thus, the domain D is given by:
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