Download presentation
Presentation is loading. Please wait.
Published byJared Martin Modified over 8 years ago
1
Introduction to Organic Chemistry and Biochemistry Instructor Dr. Upali Siriwardane (Ph.D. Ohio State) E-mail: upali@latech.edu Office: 311 Carson Taylor Hall ; Phone: 318-257-4941; Office Hours: MTW 8:00 - 10:00 am; ThF 9:00 - 10:00 am 1:00 - 2:00 pm. December 19, 2014: Test 1 (Chapters 12-13) January 26, 2015: Test 2 (Chapters 14-16) February 13, 2015: Test 3 (Chapters 17-19) March 2, 2015: Test 4 (Chapters 20-22) March 3, 2015: Make Up Exam: Chapters 12-22) Bring Scantron Sheet 882-E Chemistry 121(001) Winter 2015 1 CHEM 121 Winter 15
2
Slides & GHW Questions GHW#1 2 CHEM 121 Winter 15
3
Chapter 12. Saturated Hydrocarbons 12.1 Organic and Inorganic Compounds, 341 12.2 Bonding Characteristics of the Carbon Atom, 342 12.3 Hydrocarbons and Hydrocarbon Derivatives, 342 12.4 Alkanes: Acyclic Saturated Hydrocarbons, 343 12.5 Structural Formulas, 344 12.6 Alkane Isomerism, 346 12.7 Conformations of Alkanes, 348 12.8 IUPAC Nomenclature for Alkanes, 350 12.9 Line-Angle Structural Formulas for Alkanes, 356 12.10 Classification of Carbon Atoms, 358 12.11 Branched-Chain Alkyl Groups, 359 12.12 Cycloalkanes, 361 12.13 IUPAC Nomenclature for Cycloalkanes, 362 12.14 Isomerism in Cycloalkanes, 363 12.15 Sources of Alkanes and Cycloalkanes, 365 12.16 Physical Properties of Alkanes and Cycloalkanes, 367 12.17 Chemical Properties of Alkanes and Cycloalkanes, 368 12.18 Halogenated Alkanes and Cycloalkanes, 371 3CHEM 121 Winter 15
4
1. Circle the correct compound type (ionic or covalent) for the following: formula compound type a) NBr 3 (ionic or covalent) b) NaCl (ionic or covalent) c) C 2 H 5 OH(inorganic or organic) d) NH 4 NO 3 (inorganic or organic) 4CHEM 121 Winter 15
5
Shapes of Atomic Orbitals – A s orbital consists of sphere with the center at the nucleus – A p orbital consists of two lobes arranged in a straight line with the center at the nucleus 5CHEM 121 Winter 15
6
Shapes of p Atomic Orbitals – A p orbital consists of two lobes arranged in a straight line with the center at the nucleus 6CHEM 121 Winter 15
7
Hybridizations of Atomic Orbitals – sp 3 tetrahedral 109.5 – sp 2 trigonal planar 120 – sp linear 180 7CHEM 121 Winter 15
8
Electronic Configuration of atoms Ground state electronic configuration Ground state electronic configuration of atoms in core format Carbon (C): [He] 2s 2, 2p 2 or [He] 2s 2, 2p x 1 3p y 1 3p z 0 Potassium (K): [Ar] 4s 1 Phosphorous (P):[Ne] 3s 2, 3p 3 Valence shell electronic configuration Carbon (C): 3s 2, 3p 2 Potassium (K): 4s 1 Phosphorous (P):3s 2, 3p 3 How you get the electronic configuration of an atom from the periodic table? 8CHEM 121 Winter 15
9
2.For the atoms and ions below, circle the correct ground state valence electron configuration of carbon in core format: a)Carbon (C):2s 1, 2p x 1 2p y 1 2p z 1 b)Carbon (C): 4s 1 or 3s 2, 3p 6 c)Carbon (C):[Ne] 3s 2, 3p 3 d) Carbon (C): [He] 2s 2, 2p x 1 2p y 1 2p z 0 9CHEM 121 Winter 15
10
Lewis structure of atoms (Review) Slide - 10CHEM 121 Winter 15
11
a) N b) C 3. Circle the Lewis structures of the following atoms: 11CHEM 121 Winter 15
12
Drawing Lewis structure molecules and ions (Review) 1)Add all valence electron 1)Add all valence electron of atoms in the molecule from the formula. Add the ion charge 2) Add the ion charge for negative ions or subtract for positive ions. Draw the skeletal structure 3) Draw the skeletal structure by connecting the atoms with single bonds. Give each of the atoms an octet 4) Give each of the atoms an octet (8 e-). Adding unshared pairs of electrons Count the total number of e- 5) Count the total number of e- used through step 4 and compare to the number calculated in 12CHEM 121 Winter 15
13
a) CH 3 OH 4. Circle the correct Lewis structure for following compounds: 13CHEM 121 Winter 15
14
Electronegativities of Elements Electronegativity The ability of one atom in a molecule to attract electrons to itself. H-O-H 14CHEM 121 Winter 15
15
Classify following bonds nonpolar-covalent, polar-covalent or ionic bonds N-H 3.0 and 2.1 = 0.9 O-H 3.5 and 2.1 = 1.4 C-H 2.5 and 2.1 = 0.4 C-F 2.5 and 4.0 = 1.5 Na-Cl 0.9 and 3.0 = 2.1 Al-Cl 1.5 and 3.0 = 1.5 Pure Covalent: 0-0.4 Polar Covalent: 0.5-1.5 Ionic Bond: <1.5 15CHEM 121 Winter 15
16
5. Circle the most polar bond in the following molecule : 16CHEM 121 Winter 15
17
Classifying Organic Compounds (hydrocarbon derivatives) Examples Functional Group Ending HydrocarbonsC and H only -ane Alcohols OH R-OH -ol Haloalkanes Cl R-Cl -halide(chloride) Ethers O-R’ R-O-R’ -ether Acids COOH R-COOH -oic acid Amines NH 2 R-NH 2 -amine Ketones C=O R(C=O)R’ -one Aldehydes CHO R-CHO -al 17CHEM 121 Winter 15
18
Types of formula for organic compounds Chemical formula: Indicate the kind and number of each type of atom in the molecule. Condensed formula: Shows skeletal atoms in a molecule and places them in a sequential order that indicates bonding. Condensed Structural formula: Shows each atom and bonds in a molecule. Expanded Structural formula: Shows each atom and bonds in a molecule. Line-angle formula: The hydrogen atoms are removed from carbon chains, leaving just a carbon line skeleton with functional groups attached to it. Slide - 18CHEM 121 Winter 15
19
Acyclic Alkanes Are saturated hydrocarbons: Noncyclic alkanes: Noncyclic alkanes: General molecular formula, C n H 2n+2 Structural formula: Normal alkanes n-alkane Normal alkanes n-alkane 19CHEM 121 Winter 15
20
6. Name the functional group in each of the following molecules 20CHEM 121 Winter 15
21
7) Give the formulas for each of the following: a) i) Molecular formula: ii) Condensed formula: 21CHEM 121 Winter 15
22
7) Give the formulas for each of the following: b) i) Molecular formula: ii) Condensed formula: iii) Line-angle formula: b)b 22CHEM 121 Winter 15
23
8) Give the following for an straight alkane with five carbons atoms i) Molecular formula: ii) Condensed formula: iii) Line-angel formula: iv) IUPAC name: 23CHEM 121 Winter 15
24
24 General molecular formula: C n H 2n+2 All bond angles about tetrahedral carbon are approximately 109.5° Nomenclature: Unbranched or straight chain alkanes CHEM 121 Winter 15
25
Nomenclature: Unbranched or straight chain alkanes General molecular formula: C n H 2n+2 All bond angles about tetrahedral carbon are approximately 109.5° 25CHEM 121 Winter 15
26
Rules of IUPAC Nomenclature of Branched Alkanes Parent name: the longest carbon chain Substituent: a group bonded to the parent chain Alkyl group: a substituent derived by removal of a hydrogen from an alkane; given the symbol R- written in alphabetical order CH 4 becomes CH 3 - (methyl) CH 3 CH 3 becomes CH 3 CH 2 - (ethyl) Prefixes: di-, tri-, tetra-, etc. are not included in alphabetization 26CHEM 121 Winter 15
27
Naming Branched Alkanes Parent name: the longest carbon chain Substituent: a group bonded to the parent chain Alkyl group: a substituent derived by removal of a hydrogen from an alkane; given the symbol R- written in alphabetical order 27CHEM 121 Winter 15
28
Common alkyl groups 28CHEM 121 Winter 15 Primary H: hydrogen attached to C atom which is attached to one carbon atoms Secondary H: hydrogen attached to C atom which is attached to two carbon atoms Tertiary H: hydrogen attached to C atom which is attached to three carbon atoms
29
Common alkyl groups 29CHEM 121 Winter 15
30
9) IUPAC name of the following branched alkane: 30CHEM 121 Winter 15
31
10) Give the names of following alkyl groups: 31CHEM 121 Winter 15
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.