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2. 1.A 2.B 3.C 4.D Five Minute Check 4 (over Lesson 2-6) A.1,233 B. 1,105 C. 441 D. 265 Evaluate the expression 9(x 2 + y 2 ) for x = –4 and y = 11. Find the product of –x and y if x = –4, and y = 11. A.–44 B. –15 C. 15 D. 44 What is –3(8g) simplified? A.–38g B. –24g C. –24 + g D. –24 + 3g

3. Lesson Menu Main Idea Key Concept: Divide Integers with the Same Sign Example 3: Dividing Integers with the Same Sign Example 4: Evaluate an Expression Example 5: Real-World Example Concept Summary: Operations with Integers

4. Main Idea/Vocabulary Divide integers (2.2.8B) (M8.A.3.3.1).

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7. Example 3 Dividing Integers with Same Sign Find –12 ÷ (–2). Answer: 6 –12 ÷ (–2)=6The integers have the same sign. The quotient is positive.

8. 1.A 2.B 3.C 4.D Example 3 A.–32 B.–16 C.–3 D.3 Find –24 ÷ (–8).

9. Example 4 ALGEBRA Evaluate –18 ÷ x if x = –2. Answer: 9 Evaluate an Expression –18 ÷ x=–18 ÷ (–2)Replace x with –2. =9 Divide. The quotient is positive.

10. 1.A 2.B 3.C 4.D Example 4 A.–63 B.63 C.7 D.–7 ALGEBRA Evaluate g ÷ h if g = 21 and h = –3.

11. Example 5 PHYSICS You can find an object’s acceleration with the expression, where S f = final speed, S s = starting speed, and t = time. If a car was traveling at 80 feet per second and, after 10 seconds, is traveling at 40 feet per second, what was its acceleration?

12. Example 5 Answer: The car’s acceleration is –4 feet per second squared. = –4 Divide. Replace S f with 40, S s with 80, and t with 10. Subtract 80 from 40

13. 1.A 2.B 3.C 4.D Example 5 A.–20ºF B.–4ºF C.12ºF D.4ºF WEATHER The temperature at 4:00 P.M. was 52ºF. By 8:00 P.M., the temperature had gone down to 36ºF. What is the average change in temperature per hour?

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15. Review REVIEW: 1.51  (-3) = 2. 3.-12  (-2) = 4.Evaluate –18  x if x = -2 -17 -11 6 -18  (-2) = 9

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17. Resources Five-Minute Check (over Lesson 2–7) Image Bank Math Tools Adding Integers Comparing and Ordering Integers Subtracting Positive and Negative Integers

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