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Published bySamson Pearson Modified over 9 years ago
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Warm Up Determine a) ∞ b) 0 c) ½ d) 3/10 e) 1
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2.4 – Rates of Change and Tangent Lines
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GOAL I will be able to calculate the slope of a line tangent to a curve through the definition of the slope of a curve
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Average rate of change
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Example
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You try
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Remember Geometry? Secant line is a line which passes through at least 2 points on a curve Tangent line is a line which passes through exactly one point on a curve.
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Average rate of change=slope of the secant line Instantaneous rate of change = slope of tangent line
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Example
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Solution
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Continued
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In general: The slope of the curve f(x) at the point (a, f(a)) is Provided the limit exists.
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You try Find the slope of the curve f(x) = x 2 + x at x = 5. When you are asked to find the slope at a point a, use the interval [a, a+h]. So in this case, use [5, 5+h] Find f(5) and f(5+h). Then plug those into the slope equation.
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Solution
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Example If the function f given by f (x) = x 2 + x has an average rate of change of 7 on the interval [0, k], then k = ? (a) -8 (b) 2 (c) 6 (d) 30 (e) k cannot be determined from the information given.
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Definition The normal line to a curve at a point is the line perpendicular to the tangent line at that point. So: to find the equation of the normal line, follow the process of finding slope, then use the opposite reciprocal.
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Time check!
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Example
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Continued When is the slope equal to 9? 9= 2a+1 At a=4
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Continued
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Homework 2.4
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