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Published byBenjamin Stone Modified over 9 years ago
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Real roots can be found from the graph (x-intercepts) We use synthetic division with the real roots to solve for the imaginary roots There are as many roots as the degree, so x 5 has 5 roots. Those not seen on the graph are imaginary or multiples of real roots
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1 › Goes straight through the zero 2 › “Touch and go” at the zero (makes a U) 3 › “S” or “Wiggles” through the zero
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Quadratic Formula still: › Always comes in pairs, conjugate pairs ! You will end up with a negative under the radical!! To get rid of the negative, take out an i.
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If a + bi is a zero Then a – bi is a zero If ai is a zero Then –ai is a zero
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Imaginary zeros don’t cross x-axis!!!! They are imaginary you can’t see them on a graph.
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Find all of the zeros. Always look to see if a function will factor. This function WILL factor.
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f(x) = x 4 – 5x 3 + 7x 2 + 3x - 10 Find all the roots
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Find all of the zeros of the function: x = -2 x = 1 5 roots: 3 real 2 imag. BOUNCES!
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You Try Find All Zeros X 3 +6x 2 +20x+12
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WS for Homework #3, 4, &7 Choose any other 3 you want **Test is next THURSDAY!**
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