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Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

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Presentation on theme: "Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?"— Presentation transcript:

1 Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

2 Chapter 1 Vocab and overview

3 What do you think? Distance Point Line Plane Segment Ray Midpoint Bisector Vertex Angle Perpendicular Congruent

4 Definitions Point- indicates location has no size Line- straight path that goes on and on forever in both directions. Plane- flat surface with no end and no thickness Segment- part of a line with two end points Ray- part of a line with one end point that never ends on the other side

5 Vocabulary Coordinate Distance Congruent segments- segments of exactly the same length Midpoint- point in the middle of a segment Segment bisector- point, line, ray, or segment dividing a segment into two even pieces.

6 Lets see

7 1.Name a point in the figure. 2.Give two names for a line in the figure. 3.Give two names for the plane in the figure. Bell Ringer Page 2 top 4 lines

8 Intersection- set of all points two figures (lines, planes, shapes) share

9

10 WE DO Name a 1.Point 2.Line 3.Plane 4.Ray 5.Segment 6.Intersection

11 Segment Addition Postulate If A B and C are colinear then AB + BC = AC

12 Lets Try it

13 WE DO!! 1.If AD = 12 and AC = 4y – 36, Find the value of y. Then find AC and DC 2.IF ED = a + 4 and DB = 3a – 8, find ED, DB, and EB.

14 Vocabulary Angle Side Vertex Acute Right Obtuse Straight

15 Parts of an Angle

16 Types of Angles


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