1. Chapter 2 Review Equations of Lines
1. Give the domain and range:
{(3,2) (5,1) (-4,2) (-3,0) (3,5)}
D: {-4, -3, 3, 5} R: {0,1,2,5}
Is it a function?
NO – 3 goes to 2 and 5.

2. Slope-intercept: y = mx + b
2. Write the equation of the line with slope -3 and y-intercept 4. Graph the line.
y= -3x+4
y=-3x+4

3. Formula: y-y1 = m(x-x1) y+2 = ⅔(x-5) y+2 = ⅔x-3⅓ y = ⅔x-5⅓
Point slope: y – y1 = m( x – x1)
3. Write the equation of the line that passes through (5,-2) and has slope of ⅔.
Formula: y-y1 = m(x-x1)
y+2 = ⅔(x-5)
distribute
y+2 = ⅔x-3⅓
Subtract 2
y = ⅔x-5⅓

4. Formula: y-y1 = m(x-x1) y-4= -5(x+1) y-4=-5x-5 y = -5x-1
Point slope: y – y1 = m( x – x1)
4. Write the equation of the line that passes through (-1,4) and (-2,9)
m = = -5
Formula: y-y1 = m(x-x1)
y-4= -5(x+1)
distribute
y-4=-5x-5
add 4
y = -5x-1

5. m= 2 Formula: y-y1 = m(x-x1) y+2= 2(x-3) y+2=2x-6 y = 2x-8
Point slope: y – y1 = m( x – x1)
5. Write the equation of the line parallel to y = 2x – 7 and passes (3,-2)
m= 2
Formula: y-y1 = m(x-x1)
y+2= 2(x-3)
distribute
y+2=2x-6
Subrtact 2
y = 2x-8

6. Formula: y-y1 = m(x-x1) y-1= 4(x+3) y-1=4x+12 y = 4x+13
6. Write the equation of the line perpendicular to x + 4y = 8 and passes (-3,1)
4y = -x + 8 y = -¼x ┴ slope is 4
Formula: y-y1 = m(x-x1)
y-1= 4(x+3)
distribute
y-1=4x+12
Add 1
y = 4x+13

7. WRITE IN STANDARD FORM: Ax + By = C
7. Write the equation of the line perpendicular to 2x – 3y = 6 and passes (2,-4)
-3y = -2x + 6 y = ⅔x ┴ slope is -3/2
y+4= -3/2(x-2) y + 4 = -3/2x + 3 y = -3/2x - 1
( ) 2
2y= -3x – 2 3x + 2y = -2

8. 8. Graph the line: 5x – 2y = 8 -2y = -5x + 8 y = 5/2x - 4
Slope-intercept: y = mx + b
8. Graph the line: 5x – 2y = 8
-2y = -5x + 8
y = 5/2x - 4
y = 5/2x - 4

9. 9. Graph the inequality: 2y > 3x - 8

10. Piecewise function:
If x > -2
If x ≤ -2
f(x)=

11. 10. Graph the function: y = 3|x-4|+2
Describe the shifts:
SHIFTS OF GRAPHS
y = a|x| if a<1 get wider y = a|x| if a>1 get narrower y = |x+h| moves left h units y = |x-h| moves right h units y = |x|+k moves up k units y = |x|-k moves down k units
narrower by 3, up 2 and right 4

12. 11. Graph the function: y = -2|x+1|-3
Describe the shifts:
SHIFTS OF GRAPHS
y = a|x| if a<1 get wider y = a|x| if a>1 get narrower y = |x+h| moves left h units y = |x-h| moves right h units y = |x|+k moves up k units y = |x|-k moves down k units
Reflects across the x axis narrower by 2, down 3 and left 1.

13. HOMEWORK
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