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Published byMay Joseph Modified over 9 years ago
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(a quick how-to) Wendi Morrison 2010
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Start with data, not necessarily linear. Time (s)Distance (m) 00 10 2040 3090 40160 50250 60360 70490 80640 Distance vs. Time What was the distance at 35 s? When was the distance 200 m? Use a straight line to estimate a value between known data.
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Choose the two points that capture 35 s. Time (s)Distance (m) 00 10 2040 3090 40160 50250 60360 70490 80640 3040 10 90 160 70 35 x 5 90 + x Plot the points to make a triangle. Label what you know. Label the triangle sides. Solve the ratio: Add x to the lower value:90 + 35 = 125 The triangle is this shape because the graph goes up… Make a smaller triangle. x Round to the same precision as 35 s.
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Choose the two points that capture 200 m. Time (s)Distance (m) 00 10 2040 3090 40160 50250 60360 70490 80640 4050 10 160 250 90 40 + x 40 x 200 Round to the same precision. Plot the points to make a triangle. Label what you know. Solve the ratio: Add x to the lower value:40 + 4 = 44 Label the triangle sides. Make a smaller triangle.
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