1. “We demand rigidly defined areas of doubt and uncertainty.” Vroomfondel the philosopher, The Hitchhiker's Guide to the Galaxy Course web page http://sdbv.missouristate.edu/mreed/CLASS/PHY12 3 Cell phones put away when class begins please.

2. Announcements Reading: Chapter 2, sections 1-3; Chapter 3 section 1; and Chapter 4, all. Because of ice Wednesday, some of the examples in this lecture will be skipped over- please go back afterwards and make sure you can do and understand them.

3. Notes on tan -1 When you use tan -1 your answers will ONLY be between +90 and -90 o. +y +x +y -y -x

4. tan -1 ONLY from +90 to -90 o. So ONLY these angles are covered. And they only cover +x values. What happens if you have a -x value? +y +x -y -x

5. tan -1 ONLY from +90 to -90 o. What happens if you have a -x value? You have to add 180 0 to it. (This may give you angles larger than 180 o, but that's okay.) +y +x -y -x

6. Kinematics Chapters 2 & 3 2.1 Displacement 2.2 Speed and Velocity 2.3 Acceleration 2.7 Graphical analysis 3.1 Displacement, Velocity, and Acceleration in Two Dimensions 

7. Kinematics is defined as the branch of mechanics that studies the motion of a body without regard to the cause of the motion. (description vs. the reason why) Dynamics deals with why.

8. Variables Time – determines interval of event. Displacement – straight line distance from start to finish of event. Position – place on coordinate system which may change over time.

9. XoXo X The displacement is the difference in positions at 2 separate times. In just the X direction, this is: DX = X - X o DXDX The metric unit for distance is the meter.

10. XoXo X We use D to represent the change in something. We use o (not) to indicate an initial or starting value. DX = X - X o DXDX

11. X o =2X 2 =5X 1 =12X f =-2 A car stars at x o =2m, drives to x 1 =12m and then turns around and finally gets to x f =-2m Meters is the SI (MKS) unit of length. Examples

12. X o =2X 2 =5X 1 =12X f =-2 In this case the total displacement is DX = X f - X o = -2m – 2m = -4m, even though the distance the car went was 24m. The displacement from X 1 to X 2 is DX = X 2 - X 1 = 5m – 12m = -7m The displacement from X 0 to X 2 is DX = X 2 - X o =12m – 2m = 10m Meters is the SI (MKS) unit of length. Examples

13. In two dimensions, we just track 2 coordinates. Here, an object has gone from point P to point Q. DX = X 2 - X 1 and DY = Y 2 - Y 1 and the result is DR = (DX 2 + DY 2 ) 1/2

14. XoXo X The change of position did not happen instantly, but took some time. DX = X - X o DXDX

15. XoXo X The time it took can be written as Dt = t – t o and this gives us our definition of speed. Speed= DX/Dt Or more generally: velocity = DR/Dt DXDX The metric unit for velocity is m/s (meters per second)

16. XoXo X We all know that speed is just how fast something is moving and it is defined as distance over time. s=d/t Or more generally: velocity = DR/Dt which is a vector. DXDX

17. X o Sgf X St.L St. Louis is 215 miles from Springfield. If it takes me 2 hours to drive there, what was my average speed? s=d/t DXDX

18. XoXo X St. Louis is 215 miles from Springfield. If it takes me 2 hours to drive there, what was my average speed? s=d/t s= 215mi/2hr = 107.5mph DXDX

19. XoXo X Turn the problem around: St. Louis is 215 miles from Springfield. If I drive 70mph, how long will it take to get there? s=d/t DXDX

20. XoXo X Turn the problem around: St. Louis is 215 miles from Springfield. If I drive 70mph, how long will it take to get there? s=d/t t=d/s = 215mi/70mph = 3.07hr (3:04) DXDX

21. XoXo X *The metric system. If it took 2 seconds to go from X o to X and if X is 10m away from X o, what was the speed of the car? DXDX

22. XoXo X The metric system. If it took 2 seconds to go from X o to X and if X is 10m away from X o, what was the speed of the car? s=d/t = 10m/2s = 5 m/s. DXDX

23. XoXo X Velocity is just speed with direction. Speed: 70mph Velocity: 70mph to St. Louis DXDX

24. XoXo X Velocity is just speed with direction. DXDX

25. We have 2 formulas for velocity. Use whichever is easiest with what's given in the problem.

26. Velocity is just speed with direction. We have 2 formulas for velocity. Use whichever is easiest with what's given in the problem. e.g. Betty walked 40m in 5s, what was Betty's speed?

27. Velocity is just speed with direction. We have 2 formulas for velocity. Use whichever is easiest with what's given in the problem. e.g. Betty walked 40m in 5s, what was Betty's speed? In this case 40m is DX and 5s is Dt

28. Velocity is just speed with direction. We have 2 formulas for velocity. Use whichever is easiest with what's given in the problem. e.g. Betty walked 40m in 5s, what was Betty's speed? In this case 40m is DX and 5s is Dt S = d/t = 40/5 = 8m/s.

29. Velocity is just speed with direction. We have 2 formulas for velocity. Use whichever is easiest with what's given in the problem. e.g. Joe passed mile marker 71 at 2:15pm and at 3:15pm he passed mile marker 121.

30. Velocity is just speed with direction. We have 2 formulas for velocity. Use whichever is easiest with what's given in the problem. e.g. Joe passed mile marker 71 at 2:15pm and at 3:15pm he passed mile marker 121. The mile markers are X o and X while the times are t o and t.

31. Velocity is just speed with direction. We have 2 formulas for velocity. Use whichever is easiest with what's given in the problem. e.g. Joe passed mile marker 71 at 2:15pm and at 3:15pm he passed mile marker 121. The mile markers are X o and X while the times are t o and t. d = (X-X o )/(t-t o ) = (121-71)/(1) = 50miles/hour

32. Velocity is just speed with direction. *We have 2 formulas for velocity. Use whichever is easiest with what's given in the problem. These can also be mixed. e.g. Hilda passed mile marker 71 at 2:15pm and 3 hours later she passed mile marker 204. In this case the mile markers are X o and X, but 3 hours is Dt. Use what is at hand.

33. Velocity is just speed with direction. *These can also be mixed. e.g. Hilda passed mile marker 71 at 2:15pm and 3 hours later she passed mile marker 204. In this case the mile markers are X o and X, but 3 hours is Dt. Use what is at hand. d=s/t d = (X – X o )/  t = (204-71)/3 = 44.3 miles/hour

34. *During a two minute interval, Joe walks in a direction which takes him 4m East and 6m South. What is Joe's velocity and direction?

35. During a two minute interval, Joe walks in a direction which takes him 4m East and 6m South. What is Joe's velocity and direction? E S v=r/t

36. During a two minute interval, Joe walks in a direction which takes him 4m East and 6m South. What is Joe's velocity and direction? E S r = 7.2m v = r/t = 7.2/120 = 0.06 m/s q= 33.7 o East of South (Or 56.3 o South of East).

37. Check our understanding 1) Is the average speed of a train a vector or scalar quantity? 2) Two buses depart from Chicago, one going to New York and one to San Francisco. Each bus travels at a speed of 30m/s. Do they have equal velocities? 3) A straight track has a length of 1600m. A runner begins at the starting line, runs the full length of the track, turns around and runs halfway back. The time it takes is 5 minutes. What is the runner's average speed and what's the runner's average velocity?

38. Check our understanding 1) Scalar 2) No, because their directions are different. 3) The runner covers a total of 2400m, so her average speed is 8m/s, but the displacement is only 800m, so the velocity is only 2.7m/s.

39. Acceleration Since we don't drive at the same speed all the time, our speed changes. If the speed changes, then we have acceleration. The metric unit for acceleration is m/s 2 (meters per second squared)

40. Acceleration Acceleration (+/-) occurs when the velocity is changing. Acceleration is a vector, so it has magnitude and direction.

41. If the direction of the velocity and acceleration is in the same direction then the speed of the object is increasing. If the direction of the velocity and the acceleration are in the opposite direction then the speed is decreasing.

42. Example: Acceleration and Increasing Speed Know: Want to know acceleration:

43. Example: Acceleration and Increasing Speed Know: Want to know acceleration:

44. Example: Acceleration and Decreasing Speed Want to know acceleration:

45. Example: Acceleration and Decreasing Speed Want to know acceleration:

46. Useful formulas:

47. Accelerated Motion v f = v o + a t (can also be Dt) v f 2 = v o 2 + 2aR (can also be DR)  x = v o t + ½at 2  x = ½ (v o +v f )t These equations simply describe how something is moving.

48. UNITS ARE YOUR FRIEND SO KEEP TRACK OF THEM!

49. Thinking about acceleration. A car is at a stop. Two seconds later it is moving at 60m/s. What was its acceleration?

50. Thinking about acceleration. A car is at a stop. Two seconds later it is moving at 60m/s. What was its acceleration? In this case we have v o and v f and Dt.

51. Thinking about acceleration. A car is at a stop. Two seconds later it is moving at 60m/s. What was its acceleration? In this case we have v o and v f and Dt. A = (60 – 0)/2 = 30 m/s 2

52. Acceleration Due to Gravity At sea level the acceleration due to gravity is 9.8 m/s 2. It decreases with increasing distance from the Earth’s surface (but very slowly!). The value for the acceleration due to gravity in the English system is ~32 ft/s 2.

53. The value for the acceleration due to gravity (g) usually has a negative sign in front of it to imply it is in a downward direction – toward the Earth.

54. If the anvil is dropped from 20m, what is its speed when it hits the ground?

55. In this case, the problem gives you acceleration (gravity), initial position (20m) and final position (0m). So you need an equation that includes these 3 things, and the answer is velocity.

56. The anvil hits the ground moving at nearly 20 m/s. NOTE: you cannot take the square root of a negative number. If the answer inside the square root is negative, make it positive, but remember that the answer is in the negative direction.

57. Chapter 4: Forces and Newton's Laws of Motion

58. Newton’s 1st Law An object at rest will stay at rest unless acted upon by an outside force. AND An object at constant motion will stay at constant motion unless acted upon by an outside force.

60. What is mass? Where does it come from?

61. Spin the stone wheel: Where would it be hardest? Where would it be easiest?

62. They would all be the same!

63. Sometimes called the Law of Inertia. Inertia is that property of a body that resists a change in direction. Mass is a measure of the amount of inertia an object has.

64. Mass can be defined by how hard it is to move (in the absence of other forces).

65. Newton’s 2nd Law F = ma where: F = force in Newtons m = mass in kilograms a = acceleration in m/s 2

66. If you exert a force on an object, it will cause the object to accelerate. The amount of acceleration depends upon the mass of the object. The smaller the mass, the greater the acceleration. F = ma a = F/m

67. Example: Two rocks need to be moved off a table. The desired acceleration is 1m/s 2 and rock 1 has a mass of 0.1kg and rock 2 has a mass of 10kg. How much force needs to be applied to each rock? F=ma

68. F 2 = (1)(10) = 10 NF 1 = (1)(0.1) = 0.1 N

69. Units of force are called Newtons. 1 N = 1 kg. m/s 2 F 2 = (1)(10) = 10 NF 1 = (1)(0.1) = 0.1 N

70. A force of 1450N is applied to this car which has a mass of 1230kg. What is the acceleration?

71. 1.18 m/s 2

72. Forces have direction. What is the net force on this box? What's the first thing to do?