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Nuclear Physics Chapter 25
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3 Li lithium 6.941 1 name symbol atomic number (# of p + ) average atomic mass electrons in outer energy level
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Protons positive charge made of two up quarks and a down quark Electric charge +2/3 eElectric charge -1/3 e in the nucleus… Neutrons made of two down quarks and an up quark
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Li 7 = proton = neutron number of nucleons (mass number) Li 6 an isotope of Li mass number talks about 1 atom atomic mass is an average of all atoms
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Mass is usually expressed in amu or u 1 amu = 1/12 th the mass of a carbon 12 atom 1 amu = 1.66 x 10 -27 kg= mass of p + or n 0 an n 0 is actually about 5 x 10 -4 u more massive an e - has a mass of about 5 x 10 -4 u…hmmm
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Mass can also be expressed in MeV/c 2 rest energy (E 0 ) = MeV Mega (1 x 10 6 ) electron volt (1.60 x 10 -19 J) 1 proton = 938.3 MeV/c 2
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mass number atomic number (charge)
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The electric force between protons is repulsive There must be a force stronger than the electric force holding the nucleus together
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The Strong Force is the force that holds nucleons together. It is independent of charge, it binds neutrons and protons. It only works over very small distances (atomic).
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10 -15 m r nucleus = (1.2x10 -15 m )A 1/3 where A is the atomic number
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Stable “big” atoms have more neutrons than protons, because the electric force acts over greater distances.
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Nucleons bound together in a nucleus have less mass (energy) than unbound nucleons E bind = mc 2 binding energy is that energy that holds the nucleus together mass defect the difference in mass
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Find the total binding energy of Al 27 if it has a mass of 26.981534 u. H 1 has a mass of 1.007825 u and the mass of a n 0 is 1.008665 u. There are 931.50 MeV/u. Al is atomic # 13, so it has 13(1.007825 u) of p + and e -, = 13.101725 u. Al has 14 n 0 = 14(1.008665 u) = 14.12131 u m = (13.101725 + 14.12131) u – 26.981534 u =.241501 u x 931.50 MeV/u= 225 MeV
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Nuclear Decay Alpha Decay: an particle (He nucleus) escapes the strong force by quantum tunneling. The nucleus loses 2 p + and 2 n 0.
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Beta decay: the weak force causes an up quark to change into a down quark, or vice versa. This causes a proton to change into a neutron or vice versa. neutronprotonelectron - antineutrino
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protonneutronpositron + neutrino A thallium 208 nucleus emits a - particle (an electron). Write the equation.
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Gamma Decay: a nucleon can be in an excited state, needing to get rid of energy to reach a stable energy level. The nucleon emits a photon, but the structure of the nucleus stays the same.
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