1. All Types Balance #1 ws MAYHAN

2. 1. TYPE ________ Single Replace _____Au 2 S 3 + _____H 2  ____Au + _____H 2 S Gold III sulfide reacts with hydrogen to produce gold and dihydrogen monosulfide (hydrogen sulfide) 2 33

3. 2. TYPE ________ Decomposition ___Hg 2 CO 3  ___Hg 2 O + ___CO 2 Mercury I carbonate breaks down into mercury I oxide and carbon dioxide B

4. 3. TYPE ________ Double ___Fe 2 (SO 4 ) 3 + ___KOH  ___K 2 SO 4 + ___Fe(OH) 3 Iron III sulfate reacts with potassium hydroxide to produce potassium sulfate and iron III hydroxide 23 6

5. 4. TYPE ________ Combust ___C 4 H 10 + ___O 2  ___CO 2 + ___H 2 O Tetracarbon decahydride (butane) reacts with oxygen gas to create carbon dioxide and water 8 2 10 13

6. 5.TYPE ________ Chromium metal reacts with oxygen gas to produce chromium III oxide Synthesis ___Cr + ___O 2  ___Cr 2 O 3 23 4

7. 6. TYPE ________ Barium chloride reacts with aluminum sulfate to create barium sulfate and aluminum chloride Double ___BaCl 2 + ___Al 2 (SO 4 ) 3  ___BaSO 4 + ___AlCl 3 23 3

8. 7.TYPE ________ Tricarbon octahydride with oxygen gas to produce carbon dioxide and water Combust ___C 3 H 8 + ___O 2  ___CO 2 + ___H 2 O 34 5

9. 8. TYPE ________ Calcium chlorate breaks down into calcium chloride and oxygen Decomp ___Ca(ClO 3 ) 2  ___CaCl 2 + ___O 2 3

10. 9. TYPE ________ Calcium metal reacts with aluminum chloride to create calcium chloride and aluminum Single ___Ca + ___AlCl 3  ___CaCl 2 + ___Al MAYHAN 2 3 2 3

11. 10.TYPE ________ Dicarbon dihydride reacts with oxygen gas to create carbon dioxide and water Combust ___C 2 H 2 + ___O 2  ___CO 2 + ___H 2 O 242 5

12. 11. TYPE ________ Iron III hydroxide breaks down to Iron III oxide and water Decomp ___Fe(OH) 3  ___Fe 2 O 3 + ___H 2 O 2 3

13. 12. TYPE ________ Magnesium metal reacts with tin IV chloride to create magnesium chloride and tin. Single ___Mg + ___SnCl 4  ___MgCl 2 + ___Sn 2 2

14. 13. TYPE ________ Potassium phosphate reacts with strontium hydroxide to create potassium hydroxide and strontium phosphate Double ___K 3 PO 4 + ___Sr(OH) 2  ___KOH + ___Sr 3 (PO 4 ) 2 3 2 6