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Solving Linear Systems Algebraically Section 3-2 Solving Linear Systems Algebraically.

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Presentation on theme: "Solving Linear Systems Algebraically Section 3-2 Solving Linear Systems Algebraically."— Presentation transcript:

1 Solving Linear Systems Algebraically Section 3-2 Solving Linear Systems Algebraically

2 Steps in Elimination AKA: “Linear Combination” Steps: 1. ARRANGE equations in like terms and multiply a term to attempt to cancel out a variable 2. ADD the variables where at least one variable cancels out 3. REPLACE the value into either equation 4. CHECK the solution

3 Example 1 Solve using Elimination (2)

4 Example 1 Solve using Elimination

5 Example 1 Solve using Elimination

6 Example 2 (2) (3) Solve using Elimination

7 Example 2 4. CHECK the solution Solve using Elimination

8 2/18/2016 10:49 AM3-2 - Solving Systems through Substitution Your Turn Solve using Elimination (-3)

9 Three pizzas and four sandwiches cost $34. Three pizzas and seven sandwiches cost $41.50. How much does a pizza cost? How much does a sandwich cost? Let x = pizza Let y = sandwich (-1) Pizza cost $8 Sandwich cost $2.50

10 Let d= dimes Let q = quarters (-10) 24 dimes 76 quarters Sally has $21.40 in dimes and quarters, for a total of 100 coins. How many of each kind of coin does Sally have?

11 Assignment Page 194 (6-9, 19, 20)  Write the Problem!!!  Show ALL WORK—STEPS  Be NEAT


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