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Published byWendy Tucker Modified over 9 years ago
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Elimination Method Day 2 Today’s Objective: I can solve a system using elimination
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2x – 3y = 5 x – 2y = 4 y = -3 Step 2 Step 3 y = -3 x – 2y = 4 x – 2( ) = 4 x + 6 = 4 x = -2 Step 4 Step 5 (-2, -3) -3 2x – 3y = 5 -2( ) -2x + 4y = -8
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2x + 3y = 10 3x – 4y = -2 17x = 34 Step 2 Step 3 x = 2 2x + 3y = 10 2( ) + 3y = 10 4 + 3y = 10 3y = 6 y = 2 Step 4 Step 5 (2, 2) 2 8x + 12y = 40 3( ) 4( ) 9x – 12y = -6
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3x + 2y = 17 2x + 5y = 26 -11y = -44 Step 2 Step 3 y = 4 3x + 2y = 17 3x + 2( ) = 17 3x + 8 = 17 3x = 9 x = 3 Step 4 Step 5 (3, 4) 4 6x + 4y = 34 -3( ) 2( ) -6x – 15y = -78
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Answers for Elimination 2 1.(2, 3)2. (-1, -2) 3. (1, -2) 4.(0, 3)5. (1, -4)6. (2, -2) 7.(-2, 4)8. (-5, 0)9. (2, 1) 10. (5, 2)11. (1, 4)12. (-1, -1)
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I can solve a system using elimination. Assignment WS Solving System of Equations Elimination 2
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