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CS 15-251 Lecture 8 Developing Your Counting Muscles
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Addition Rule Let A and B be two disjoint, finite sets. The size of A B is the sum of the size of A and the size of B.
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Correspondence Principle If two finite sets can be placed into 1-1 onto correspondence, then they have the same size.
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Product Rule Suppose that all objects of a certain type can be constructed by a sequence of choices with P 1 possibilities for the first choice, P 2 for the second, and so on. IF 1) Each sequence of choices constructs some object AND 2) Each object has exactly one sequence that constructs it THEN there are P 1 P 2 P 3 …P n objects of that type.
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The Sleuth’s Criterion Condition (2) of the product rule: For any object it should be possible to reconstruct the sequence of choices that lead to it.
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The number of subsets of size r that can be formed from an n-element set is:
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How many sequences of seven letters contain at least 2 of the same letter? 26 7 – 26*25*24*23*22*21*20
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Counting Poker Hands…
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52 Card Deck 5 card hands 4 possible suits: 13 possible ranks: 2,3,4,5,6,7,8,9,10,J,Q,K,A
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52 Card Deck 5 card hands 4 possible suits: 13 possible ranks: 2,3,4,5,6,7,8,9,10,J,Q,K,A Pair: set of two cards of the same rank Straight: 5 cards of consecutive rank Flush: set of 5 cards with the same suit
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Ranked Poker Hands Straight Flush A straight and a flush 4 of a kind 4 cards of the same rank Full House 3 of one kind and 2 of anotherFlush A flush, but not a straightStraight A straight, but not a flush 3 of a kind 3 of the same rank, but not a full house or 4 of a kind 2 Pair 2 pairs, but not 4 of a kind or a full house A Pair
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Straight Flush
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4 Of A Kind
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Flush
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Straight
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3 Of A Kind
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Question: How many ways to rearrange the letters in the word “SYSTEMS” ?
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SYSTEMS 1) 1)7 places to put the Y, 6 places to put the T, 5 places to put the E, 4 places to put the M, and the S’s are forced. 7 X 6 X 5 X 4 = 8402)
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SYSTEMS 3) Let’s pretend that the S’s are distinct: S 1 YS 2 TEMS 3 There are 7! permutations of S 1 YS 2 TEMS 3 But when we stop pretending we see that we have counted each arrangement of SYSTEMS 3! times, once for each of 3! rearrangements of S 1 S 2 S 3.
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Arrange n symbols r 1 of type 1, r 2 of type 2, …, r k of type k
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CARNEGIEMELLON
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What is a closed form expression for c k ?
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What is a closed for expression for c n ? n times Before combining like terms, when we multiply things out we get 2 n cross terms. There is a natural correspondence between sequences with k X’s and (n-k) 1’s and cross terms evaluating to X k.
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The Binomial Formula binomial expression Binomial Coefficients
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The Binomial Formula (1+X) 1 = (1+X) 0 = (1+X) 2 = (1+X) 3 = 1 1 + 1X 1 + 2X + 1X 2 1 + 3X + 3X 2 + 1X 3 (1+X) 4 = 1 + 4X + 6X 2 + 4X 3 + 1X 4
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The Binomial Formula
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What is the coefficient of EMSTY in the expansion of (E + M + S + T + Y) 5 ? 5!
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What is the coefficient of EMS 3 TY in the expansion of (E + M + S + T + Y) 7 ? The number of ways to rearrange the letters in the word SYSTEMS.
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What is the coefficient of BA 3 N 2 in the expansion of (B + A + N) 6 ? The number of ways to rearrange the letters in the word BANANA.
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What is the coefficient of in the expansion of (X 1 +X 2 +X 3 +…+X k ) n ?
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The Multinomial Formula
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Multinomial Coefficients
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5 distinct pirates want to divide 20 identical, indivisible bars of gold How many different ways to divide up the loot?
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Sequences with 20 G’s and 4 /’s GG/G//GGGGGGGGGGGGGGGGG/ represents the following division among the pirates: 2, 1, 0, 17, 0 In general, the i th pirate gets the number of G’s after / i-1 and before / i. This gives a correspondence between divisions of the gold and sequences with 20 G’s and 4 /’s.
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Sequences with 20 G’s and 4 /’s How many different ways to divide up the loot? Sequences with 20 G’s and 4 /’s
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How many different ways can n distinct pirates divide k identical, indivisible bars of gold?
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How many integer solutions to the following equations?
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Counting with repetitions allowed Suppose that we roll seven dice. How many different outcomes are there? 6767 What if order doesn’t matter? (E.g., Yahtzee)
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Counting with repetitions allowed How many ways are there of choosing k items from n items, where an item may be chosen more than once, but order doesn’t matter? E.g., the following are equivalent: 2 1 3 2 6 2 1, 1 3 2 1 2 2 6, 1 1 2 2 2 3 6 C C / C C C / C / / / C Place n-1 partitions / among k choices C
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Back to the pirates How many ways are there of choosing 20 pirates from a set of 5, with repetitions allowed?
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Future homework problem:
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