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Pg. 255/268 Homework Pg. 277#32 – 40 all Pg. 310#1, 2, 7, 41 – 48 #6 left 2, up 4#14Graph #24 x = #28x = 6 #35 Graph#51r = 6.35, h = 9, V = 380 #1 Graph#3a)

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Presentation on theme: "Pg. 255/268 Homework Pg. 277#32 – 40 all Pg. 310#1, 2, 7, 41 – 48 #6 left 2, up 4#14Graph #24 x = #28x = 6 #35 Graph#51r = 6.35, h = 9, V = 380 #1 Graph#3a)"— Presentation transcript:

1 Pg. 255/268 Homework Pg. 277#32 – 40 all Pg. 310#1, 2, 7, 41 – 48 #6 left 2, up 4#14Graph #24 x = #28x = 6 #35 Graph#51r = 6.35, h = 9, V = 380 #1 Graph#3a) dec b) inc c) dec #5 Down 4#6Stretch 3 #7 Right 3#8Reflect x and y axes #9 Left 1, Up 7#15a = c

2 5.1 Exponential Functions Life Span Problems The formula for Life Span problems is similar to the continuous growth/decay equation using e. Population: Life Span: Suppose the half-life of a certain radioactive substance is 20 days and there are 5g present initially. – Write an equation to represent the situation. – Draw a complete graph. – Find when there will be less than 1g of the substance remaining.

3 5.2 Simple and Compound Interest Compound Interest Compound Interest is when financial institutions pay interest on the interest. (Yay… more money!) Suppose P dollars are invested at an interest rate r, then the compound interest formula for the total amount S after n interest periods is: Example Sally invests $500 at 7% interest compounded annually. Find the value of the investment after 10 years. How much should Sally invested at 6.25% compounded semi-annually in order to have an investment of $1,500 after 5 years?

4 5.2 Simple and Compound Interest Compound Interest Sally invests $1000 at 8%. Find the value of the investment after one year when it is compounded – Annually – Quarterly – Monthly – Weekly – Daily – Hourly – Continuously Continuous Interest If P dollars are invested at an APR, r, (in decimal form) and compounded continuously, then the value of the investment after t years is given by: S = Pe rt


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