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5.7 Graphs of Quadratic Inequalities p. 271. Forms of Quadratic Inequalities y<ax 2 +bx+cy>ax 2 +bx+c y≤ax 2 +bx+cy≥ax 2 +bx+c Graphs will look like a.

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Presentation on theme: "5.7 Graphs of Quadratic Inequalities p. 271. Forms of Quadratic Inequalities y<ax 2 +bx+cy>ax 2 +bx+c y≤ax 2 +bx+cy≥ax 2 +bx+c Graphs will look like a."— Presentation transcript:

1 5.7 Graphs of Quadratic Inequalities p. 271

2 Forms of Quadratic Inequalities y<ax 2 +bx+cy>ax 2 +bx+c y≤ax 2 +bx+cy≥ax 2 +bx+c Graphs will look like a parabola with a solid or dotted line and a shaded section. The graph could be shaded inside the parabola or outside.

3 Steps for graphing 1. Sketch the parabola y=ax 2 +bx+c (dotted line for < or >, solid line for ≤ or ≥) ** remember to use 5 points for the graph! 2. Choose a test point and see whether it is a solution of the inequality. 3. Shade the appropriate region. (if the point is a solution, shade where the point is, if it’s not a solution, shade the other region)

4 Example: Graph y ≤ x 2 +6x- 4 * Vertex: (-3,-13) * Opens up, solid line Test Point: (0,0) 0≤0 2 +6(0)-4 0≤-4 So, shade where the point is NOT! Test point

5 Graph: y>-x 2 +4x-3 * Opens down, dotted line. * Vertex: (2,1) * Test point (0,0) 0>-0 2 +4(0)-3 0>-3 x y 0 -3 1 0 2 1 3 0 4 -3 Test Point

6 Last Example! Sketch the intersection of the given inequalities. 1 y≥x 2 and 2 y≤-x 2 +2x+4 Graph both on the same coordinate plane. The place where the shadings overlap is the solution. Vertex of #1: (0,0) Other points: (-2,4), (-1,1), (1,1), (2,4) Vertex of #2: (1,5) Other points: (-1,1), (0,4), (2,4), (3,1) * Test point (1,0): doesn’t work in #1, works in #2. SOLUTION!

7 Assignment


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