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CIRCLES Everything you wanted to know and then some!!
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Parts of a Circle Circle – set of all points _________ from a given point called the _____ of the circle. C Symbol: equidistant center C
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Secant Line A secant line intersects the circle at exactly TWO points.
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TANGENT: a LINE that intersects the circle exactly ONE time
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Name the term that best describes the line. Secant Radius Diameter Chord Tangent
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If a line (segment or ray) is tangent to a circle, then it is perpendicular to the radius drawn to the point of tangency. Point of Tangency More Pythagorean Theorem type problems! Yeah!!
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a 2 + b 2 = c 2 x = 15 9 2 + 12 2 = x 2
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R S T If two segments from the same exterior point are tangent to a circle, then they are congruent. Party hat problems!
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A C B
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P A B C Central Angle : An Angle whose vertex is at the center of the circle Minor ArcMajor Arc Less than 180° More than 180° AB ACB To name: use 2 letters To name: use 3 letters APB is a Central Angle
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measure of an arc = measure of central angle A B C Q 96 m AB m ACB m AE E = = = 96° 264° 84°
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Tell me the measure of the following arcs. 80 100 40 140 A B C D R m DAB = m BCA = 240 260
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Inscribed Angle: An angle whose vertex is on the circle and whose sides are chords of the circle INSCRIBED ANGLE INTERCEPTED ARC
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160 80 To find the measure of an inscribed angle…
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120 x What do we call this type of angle? What is the value of x? y What do we call this type of angle?How do we solve for y? The measure of the inscribed angle is HALF the measure of the inscribed arc!!
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Examples 3. If m JK = 80 , find m JMK. M Q K S J 4. If m MKS = 56 , find m MS. 40 112
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72 If two inscribed angles intercept the same arc, then they are congruent.
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Case I: Vertex is ON the circle ANGLE ARC ANGLE ARC
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Ex. 2 Find m1. 84 ° 1 m 1 = 42
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Case II: Vertex is inside the circle A B C D ANGLE ARC
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Ex. 4 Find m1. A B C D 1 93° 113° m 1 = 103
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Case III: Vertex is outside the circle A B C D ANGLE LARGE ARC small ARC ANGLE LARGE ARC small ARC LARGE ARC ANGLE
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A B Ex. 7 Find mAB. 27° 70° mAB = 16
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1 Ex. 8 Find m1. 260° m 1 = 80
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a b c d ab = cd
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9 2 6 x x = 3 3 2 1212 x x = 8 3 26 x x = 1 Ex: 1 Solve for x.
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EAB C D EA EB = EC ED
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E A B C D 7 13 4 x 7 (7 + 13) 4 (4 + x) = Ex: 3 Solve for x. 140 = 16 + 4x 124 = 4x x = 31
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E A B C EA 2 = EB EC
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E A B C 24 12 x 24 2 =12 (12 + x) 576 = 144 + 12x x = 36 Ex: 5 Solve for x.
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