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EXAMPLE 1 Find measures of arcs RS a. RTS b. RST c. SOLUTION RS is a minor arc, so mRS = m RPS = 110 o. a. RTS is a major arc, so mRTS = 360 o 110 o =

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Presentation on theme: "EXAMPLE 1 Find measures of arcs RS a. RTS b. RST c. SOLUTION RS is a minor arc, so mRS = m RPS = 110 o. a. RTS is a major arc, so mRTS = 360 o 110 o ="— Presentation transcript:

1 EXAMPLE 1 Find measures of arcs RS a. RTS b. RST c. SOLUTION RS is a minor arc, so mRS = m RPS = 110 o. a. RTS is a major arc, so mRTS = 360 o 110 o = 250 o. b. – Find the measure of each arc of P, where RT is a diameter. c. RT is a diameter, so RST is a semicircle, and mRST = 180 o.

2 EXAMPLE 2 Find measures of arcs A recent survey asked teenagers if they would rather meet a famous musician, athlete, actor, inventor, or other person. The results are shown in the circle graph. Find the indicated arc measures. Survey a. mAC SOLUTION a. mAC mAB =+ mBC = 29 o + 108 o = 137 o

3 EXAMPLE 2 Find measures of arcs b. mACD = mAC + mCD = 137 o + 83 o = 220 o A recent survey asked teenagers if they would rather meet a famous musician, athlete, actor, inventor, or other person. The results are shown in the circle graph. Find the indicated arc measures. Survey SOLUTION b. mACD

4 EXAMPLE 2 Find measures of arcs mADC mAC = 360 o – c. = 360 o – 137 o = 223 o A recent survey asked teenagers if they would rather meet a famous musician, athlete, actor, inventor, or other person. The results are shown in the circle graph. Find the indicated arc measures. Survey SOLUTION c. mADC

5 EXAMPLE 2 Find measures of arcs d. mEBD = 360 o – mED = 360 o – 61 o = 299 o d. mEBD A recent survey asked teenagers if they would rather meet a famous musician, athlete, actor, inventor, or other person. The results are shown in the circle graph. Find the indicated arc measures. Survey SOLUTION

6 GUIDED PRACTICE for Examples 1 and 2 Identify the given arc as a major arc, minor arc, or semicircle, and find the measure of the arc.

7 TQ is a minor arc, so m TQ = 120 o. GUIDED PRACTICE for Examples 1 and 2 1. TQ SOLUTION. QRT2 SOLUTION QRT is a major arc, so m QRT= 240 o.

8 GUIDED PRACTICE for Examples 1 and 2. TQR3 SOLUTION TQR is a semicircle, so m TQR = 180 o.. QS4 SOLUTION QS is a minor arc, so m QS = 160 o.

9 GUIDED PRACTICE for Examples 1 and 2. TS5 SOLUTION TS is a minor arc, so m TS = 80 o.. RST6 SOLUTION RST is a semicircle, so m RST = 180 o.

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