1. Solubility Product (K sp ) Everything dissolves in water to a point.

2. K sp expressions CaF 2 (s)  K sp = [Ca 2+ ][F - ] 2 K sp is really no different than any other K so far. Ca 2+ (aq) + 2 F - (aq)

3. Calculating K sp form solubility(M) The solubility of Bi 2 S 3 is 1.0 x 10 -15 M, calculate the K sp for Bi 2 S 3. Write dissociation equation. Bi 2 S 3 (s)  I 1.0 x 10 -15 0 0 C +(2)(1.0 x 10 -15 )+(3)(1.0 x 10 -15 ) E 2.0 x 10 -15 3.0 x 10 -15 K sp = [Bi 3+ ] 2 [S 2- ] 3 =1.1 x 10 -73 2 Bi 3+ (aq) + 3 S 2- (aq) =(2.0 x 10 -15 ) 2 (3.0 x 10 -15 ) 3

4. Calculating Solubility from K sp Calculate the solubility of copper (II) iodate from its K sp value of 1.4 x 10 -7. Cu(IO 3 ) 2 (aq)  IM 00 C +X+2X E X2X K sp = [Cu 2+ ][IO 3 - ] 2 4X 3 = 1.4 x 10 -7 X = 3.3 x 10 -3 M Cu(IO 3 ) 2 Cu 2+ (aq) + 2 IO 3 – (aq) = (X)(2X) 2 = 1.4 x 10 -7