1. Leo Lam © 2010-2012 Signals and Systems EE235 Lecture 19

2. Leo Lam © 2010-2012 Stanford The Stanford Linear Accelerator Center was known as SLAC, until the big earthquake, when it became known as SPLAC. SPLAC? Stanford Piecewise Linear Accelerator.

3. Leo Lam © 2010-2012 Today’s menu LCCDE!

4. Zero input response (example) Leo Lam © 2010-2012 4 4 steps to solving Differential Equations: Step 1. Find the zero-input response = natural response y n (t) Step 2. Find the Particular Solution y p (t) Step 3. Combine the two Step 4. Determine the unknown constants using initial conditions

5. From earlier Leo Lam © 2010-2012 5 Solve Guess solution: Substitute: We found: Solution: Characteristic roots = natural frequencies/ eigenvalues Unknown constants: Need initial conditions

6. Zero-state output of LTI system Leo Lam © 2010-2012 6 Response to our input x(t) LTI system: characterize the zero-state with h(t) Initial conditions are zero (characterizing zero-state output) Zero-state output: Total response(t)=Zero-input response (t)+Zero-state output(t) T  (t) h(t)

7. Zero-state output of LTI system Leo Lam © 2010-2012 7 Zero-input response: Zero-state output: Total response: Total response(t)=Zero-input response (t)+Zero-state output(t) “Zero-state”:  (t) is an input only at t=0 Also called: Particular Solution (PS) or Forced Solution

8. Zero-state output of LTI system Leo Lam © 2010-2012 8 Finding zero-state output (Particular Solution) Solve: Or: Guess and check Guess based on x(t)

9. Trial solutions for Particular Solutions Leo Lam © 2010-2012 9 Guess based on x(t) Input signal for time t> 0 x(t) Guess for the particular function y P

10. Particular Solution (example) Leo Lam © 2010-2012 10 Find the PS (All initial conditions = 0): Looking at the table: Guess: Its derivatives:

11. Particular Solution (example) Leo Lam © 2010-2012 11 Substitute with its derivatives: Compare:

12. Particular Solution (example) Leo Lam © 2010-2012 12 From We get: And so:

13. Particular Solution (example) Leo Lam © 2010-2012 13 Note this PS does not satisfy the initial conditions! Not 0!

14. Natural Response (doing it backwards) Leo Lam © 2010-2012 14 Guess: Characteristic equation: Therefore:

15. Complete solution (example) Leo Lam © 2010-2012 15 We have Complete Sol n : Derivative:

16. Complete solution (example) Leo Lam © 2010-2012 16 Last step: Find C 1 and C 2 Complete Sol n : Derivative: Subtituting: Two equations Two unknowns

17. Complete solution (example) Leo Lam © 2010-2012 17 Last step: Find C 1 and C 2 Solving: Subtitute back: Then add u(t): y n ( t ) y p ( t ) y ( t )

18. Another example Leo Lam © 2010-2012 18 Solve: Homogeneous equation for natural response: Characteristic Equation: Therefore: Input x(t)

19. Another example Leo Lam © 2010-2012 19 Solve: Particular Solution for Table lookup: Subtituting: Solving: b=-1, =-2 No change in frequency! Input signal for time t> 0 x(t) Guess for the particular function y P

20. Another example Leo Lam © 2010-2012 20 Solve: Total response: Solve for C with given initial condition y(0)=3 Tada!

21. Stability for LCCDE Leo Lam © 2010-2012 21 Stable with all Re( j <0 Given: A negative means decaying exponentials Characteristic modes

22. Stability for LCCDE Leo Lam © 2010-2012 22 Graphically Stable with all Re( j )<0 “Marginally Stable” if Re( j )=0 IAOW: BIBO Stable iff Re(eigenvalues)<0 Im Re Roots over here are stable

23. Leo Lam © 2010-2012 Summary Differential equation as LTI system