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Published byBertram Golden Modified over 9 years ago
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C programming---Pointers The first step: visualizing what pointers represent at the machine level. In most modern computers, main memory is divided into bytes. Each byte can hold 8 bits of information: 10100011 Each byte has a unique address in memory.
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Address 00110011 10101010 00000111 11111000 10000100 AddressContents 0 1 2 3 n-1
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Address int i = 9; /* suppose sizeof(int) = 4 The address of variable i is 0xFA83 0xFA83 0xFA84 0xFA85 0xFA86
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Pointer Variables Use a pointer variable p to store the address of a variable i, and we say p “points to” i 0xFA83 0xFA84 0xFA85 0xFA86 p
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Declaring Pointer Variables int *p; // p is a pointer variable capable of pointing to objects of type int char *str; double *q; C requires that every pointer variable point to objects of a particular type(the referenced type) There are no restrictions on what referenced type may be. In fact, a pointer variable can even point to another pointer.
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The Address and Indirection Operators int i, *p; ……. p = &i; int i; int *p = &i; int i, p = &i;
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The Address and Indirection Operators printf(“%d\n”, *p); j = *&i;
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The Address and Indirection Operators int i, *p = &i; i = 1; printf(“i = %d\n”, i); printf(“*p = %d\n”, *p); *p = 4; printf(“i = %d\n”, i); printf(“*p = %d\n”, *p);
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Something to remember Never apply the indirection operator to an uninitialized pointer variable. int *p; printf(“%d”, *p); Unless you know where a pointer points to, do not make an assignment to the pointer
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Pointer Assignment int i, j, *p, *q; p = *i; q = p; p q i
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Pointer Assignment int i, j, *p, *q; p = &i; q = &j; *q = *p; p q i
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Pointer as Arguments Example 2.c
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Using const to Protect Arguments When we call a function and pass it a pointer to a variable, we normally assume that the function will modify the variable. Sometimes we just want to examine the value of a variable, not change it. Using pointer might be efficient: time and memory space void f(const int *p) { *p = 0; // wrong: p is a pointer to a “constant integer” }
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Pointers as Return Values int *max(int *a, int *b) { if(*a > *b) return a; else return b; } int *p = max(&a, &b);
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Be careful int *f(void) { int a; …… return &a; }
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Pointers and Arrays Pointer Arithmetic int a[10], *p; p = &a[0]; a p
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Pointer Arithmetic p p = &a[2]; q = p + 3; p += 4; q
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Comparing Pointers Using the relational operators(, >=) and the equality operator (== and !=) int *p = &a[5]; int *q = &a[1]; The value of p <= q is 0(false) The value of p >= q is 1(true)
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Using Pointers for Array Processing #define N 10 int a[N], sum, *p; sum = 0; for(p = &a[0]; p < &a[N]; p++) sum += *p;
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Combining the * and ++ Operators *p++ or *(p++) (*p)++ *++p or *(++p) ++*p or ++(*p) The postfix version of ++ takes precedence over * See 3.c
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Using an Array Name as a Pointer int a[10]; *a = 7; // modify a[0] *(a + 2) = 13; // modify a[2] while( *a != 0 ) a++; // wrong
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Array Arguments int find_largest(int a[], int n) { } int find_largest(int *a, int n) { }
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Using a Pointer as an Array Name #define N 10 ….. int a[N], i, sum = 0, *p = a; ….. for(i =0; i < N; i++) sum += p[i];
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Pointers and Multidimensional Arrays int a[NUM_ROWS][NUM_COLS]; int row, col; for(row = 0; row < NUM_ROWS; row++) a[row][col] = 0; int *p; for(p = &a[0][0]; p <= &a[NUM_ROWS- 1][NUM_COLS]; p++) *p = 0;
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