Download presentation
Presentation is loading. Please wait.
Published byJemima Hancock Modified over 8 years ago
1
Limits - Substitution
2
As x approaches 3 from both directions, y approaches 8 We can find the limit by substituting x = 3 into the equation
3
Practice Answer: The limit is 24
4
When we try to substitute into we get which is undefined. If we draw the graph we find that we get a straight line with equation
5
The hole in the graph at x = 1 is a discontinuity. y has a value for every x except x = 1. i.e.
6
You can recognise a discontinuity because you need to lift your pen to continue your graph. The graph below is continuous because we can draw it without having to lift the pen.
7
Although, we do have a limit at x = 1.
8
Two methods to find the limit. Method 1 Now substitute x = 1 to get a limit of 2 i.e.
9
Method 2 Use L’Hospital’s Rule Note: Only use this when substitution gives 0/0
10
Practice Answer: Substituting gives Using either factorising or L’Hospital’s Rule: Limit is
11
Discontinuities and limits
12
f(0.5) = 3 (Solid dot gives the value at 0.5)
13
But
14
Not all discontinuities have a limit
15
Jump discontinuity
16
The graph is not heading towards the same value so there is no limit. Tends towards 1 Tends towards -1
17
Limit at x = -4 does not exist
18
Vertical asymptotoes: Limit does not exist.
19
Note: this is NOT a discontinuity f(1) =2 and
20
More Limits Divide top and bottom by x
21
When bottom power is greater than top power
22
When top power is greater than bottom power
24
Worksheet 1
25
What do you think the limit is at x = 0?
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.