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Rates of Change & Limits
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Limits in a nutshell – The limit (L) of a function is the value the function (y) approaches as the value of (x) approaches a given value Got it? No? Really??
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Example 1. f(x) = 3x + 1 x11.51.91.99 f(x)45.56.76.97
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Example 1. f(x) = 3x + 1 x11.51.91.99 f(x)45.56.76.97 x2.0012.12.53 f(x)7.003
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Example 1. f(x) = 3x + 1 As x approaches 2 from the left and from the right, the function is CONVERGING to 7.
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So, f(x)
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Easy, right? Well, we could have simply just plugged the number into the x-value in f(x) and found our answer. So what is all the fuss about? No fuss, if the graph is continuous. f(2) = 3(2) + 1 = 7 There’s lot’s of fuss if there are gaps.
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xf(x) 0.52.5 1.04 1.55.5 2.0Err. 2.58.5
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xf(x) 0.52.5 1.04 1.55.5 2.0Err. 2.58.5 What’s the “intent” of the graph as x 2?
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I guess we could have done the following: But, if we simply substituted 2 into the equation, we get something very bad
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What went wrong?
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We have a point of discontinuity at x = 2
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Many times you are asked, “What if at x = 2, the function does whatever?” … Who cares? As x gets closer and closer to the special x-number, but it never gets there, what happens? … Who cares? These questions have no effect on the limit problem (except for continuous functions) The limit stays the same.
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WAKE UP!!! If you’ve been sleeping up to now… WAKE UP!!
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Examples from Page 346
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OR
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Examples from Page 346
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Homework Page 346 Numbers 1 - 4
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14B Limits Involving Infinity
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We need to think about what happens to a function not at a certain value, but at extremes like infinity.
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Complete the following table for the function: x f(x) 2½ 10 100 200 500 700 1000 10,000 100,000
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Complete the following table for the function: x f(x) 2½ 100.10 1000.01 2000.005 5000.002 7000.00143 10000.001 10,0000.0001 100,0000.00001
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Complete the following table for the function: x f(x) 2½ 100.10 1000.01 2000.005 5000.002 7000.00143 10000.001 10,0000.0001 100,0000.00001
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Complete the following table for the function: x f(x) 2½ 100.10 1000.01 2000.005 5000.002 7000.00143 10000.001 10,0000.0001 100,0000.00001
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Complete the following table for the function: x f(x) 2½ 100.10 1000.01 2000.005 5000.002 7000.00143 10000.001 10,0000.0001 100,0000.00001
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Complete the following table for the function: x f(x) 2½ 100.10 1000.01 2000.005 5000.002 7000.00143 10000.001 10,0000.0001 100,0000.00001
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Complete the following table for the function: x f(x) 2½ 100.10 1000.01 2000.005 5000.002 7000.00143 10000.001 10,0000.0001 100,0000.00001
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Complete the following table for the function: x f(x) 2½ 100.10 1000.01 2000.005 5000.002 7000.00143 10000.001 10,0000.0001 100,0000.00001
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Complete the following table for the function: x f(x) 2½ 100.10 1000.01 2000.005 5000.002 7000.00143 10000.001 10,0000.0001 100,0000.00001
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What about if it goes towards negative infinity?
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Let’s look at it graphically
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If the degree of the denominator is greater than the numerator, then. If the degree is Bigger On Bottom its 0. BOB0. (y = 0)
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We can ignore the (-9) and the (+ 12). They really do not add anything to the graph when you go to ±∞
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So, let’s look at this graphically
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As the graph approaches ±∞, what is the “height” of the graph?
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If the degree of the denominator is greater than the numerator, then. If the degree is Bigger On Bottom its 0. BOB0. (y = 0)
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Bigger On Top, there’s No horizontal asymptote. BOTN
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Degrees of both the numerator and denominator are equal Then divide the leading coefficients. That’s your horizontal asymptote. EATS-D/C.
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Page 349 1a) i. There are going to be some new symbols. As x 0 - f(x) -∞ Vertical Asymptote x = 0 As x 0 + f(x) ∞
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Page 349 1a) i. As x ∞ x -∞ Horizontal Asymptote x = 0 f(x) 0 + f(x) 0 -
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Page 349 1a) ii.
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Homework Page 349 Numbers 1 - 3
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Problem You are hanging out at your girlfriend’s place and she goes to get you a couple of slices of pizza. Her annoying cat is looking at you and you get this great idea for a calculus experiment. Because cats have nine lives and always land on their feet, you figure no harm can come from this. So, you drop her cat out of her second-story room window. Here’s the formula that tells you how far the cat “jumped” after a given number of seconds (ignoring air- resistance): h(t) = 16t 2. (in fps)
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Distance = (rate)(time) Please make a table of the average speed for the first 5 seconds. tAvg. Speed 00 1 2 3 4 5
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Distance = (rate)(time) Please make a table of the average speed for the first 5 seconds. tAvg. Speed 00 1 2 3 4 5 16 h(t) = 16t 2
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Distance = (rate)(time) Please make a table of the average speed for the first 5 seconds. tAvg. Speed 00 1 2 3 4 5 16 h(t) = 16t 2 32
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Distance = (rate)(time) Please make a table of the average speed for the first 5 seconds. tAvg. Speed 00 1 2 3 4 5 16 h(t) = 16t 2 32 48
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Distance = (rate)(time) Please make a table of the average speed for the first 5 seconds. tAvg. Speed 00 1 2 3 4 5 16 h(t) = 16t 2 32 48 64
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Distance = (rate)(time) Please make a table of the average speed for the first 5 seconds. tAvg. Speed 00 1 2 3 4 5 16 h(t) = 16t 2 32 48 64 80
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What if you wanted to determine the cat’s speed exactly 2 seconds after it “jumped”?
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The cat is traveling about 16 fps. This is nice, but what if I wanted to know the EXACT speed 1 second after the jumped. The table gives an average. I want to know EXACT speed. See, the cat speeds up between 1 and 2 seconds and so on. Let’s look at the speed between 1.5 and 1 second
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The cat is traveling about 40 fps.
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The cat is traveling about 38.4 fps.
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The cat is traveling about 27 fps.
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The cat is traveling about 35 fps.
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The cat is traveling about 32.0 fps.
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As t gets closer and closer to 1 second, the average speed appears to get closer and closer to 32 fps.
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Making things difficult Of course, mathematicians have to make things fancy, so here’s the formula we used for average speed between 1 second and t seconds: Average Speed =
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Suppose you drive 200 miles, and it takes you 4 hours. Then your average speed is: If you look at your speedometer during this trip, it might read 65 mph. This is your instantaneous speed.
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A rock falls from a high cliff. The position of the rock is given by: After 2 seconds: average speed: What is the instantaneous speed at 2 seconds?
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for some very small change in t where h = some very small change in t Evaluate this expression for smaller and smaller values of h using your calculator.
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1 80 0.165.6.0164.16.00164.016.0001 64.0016.0000164.0002 We can see that the velocity approaches 64 ft/sec as h becomes very small. We say that the velocity has a limiting value of 64 as h approaches zero. (Note that h never actually becomes zero.)
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The limit as h approaches zero: 0
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Consider: What happens as x approaches zero? Graphically: WINDOW Y= GRAPH
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Looks like y=1
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Numerically: TblSet You can scroll down to see more values. TABLE Tbl Start-0.3 ΔTbl0.1 XY1Y1 -0.30.98507 -0.20.99335 -0.10.99833 0ERR:.10.99833.20.99335.30.98507
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It appears that the limit of as x approaches zero is 1
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Limit notation: “The limit of f of x as x approaches c is L.” So:
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Find the solutions a.) b.)
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Having fun with SUBS Find the solutions a.) b.)
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THE PRODUCT RULE Solve Graphically a.)
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Product Rule Cont’d Confirm Algebraically
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Exists or Not?
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The limit of a function refers to the value that the function approaches, not the actual value (if any). not 1
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Properties of Limits: Limits can be added, subtracted, multiplied, multiplied by a constant, divided, and raised to a power. (See page 58 for details.) For a limit to exist, the function must approach the same value from both sides. One-sided limits approach from either the left or right side only.
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1234 1 2 At x=1:left hand limit right hand limit value of the function does not exist because the left and right hand limits do not match!
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At x=2:left hand limit right hand limit value of the function because the left and right hand limits match. 1234 1 2
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At x=3:left hand limit right hand limit value of the function because the left and right hand limits match. 1234 1 2
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The Sandwich Theorem: Show that: The maximum value of sine is 1, soThe minimum value of sine is -1, soSo:
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By the sandwich theorem: Y= WINDOW Y1 = X2X2 Y2 = -x 2 Y3X 2 Sin(1/x)
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Thought for the Day I hope that someday we will be able to put away our fears and prejudices and just laugh at people.
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Homework 2.1a 1-9, 15, 16
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