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Published byBaldwin Cunningham Modified over 8 years ago
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Mirrors - Practice Problems If you can do these, You will do well! Holt Physics
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Mathematical prediction of image Location Where f is the focal length (remember to assign it a sign), d o is the object distance, and d i is the image distance Height Where h i is the image height, h o is the object height, and d i is the image distance, and d o is the object distance Magnification Where h i is the image height, h o is the object height, and d i is the image distance, and d o is the object distance
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The Variables Used f – Focal length Focus (name of location) d o – Object distance d i – Image distance C – Radius of curvature Center of curvature (location) These values are distances. The principle axis can be considered a number line for which the mirror is the origin and the object determines the positive side of the number line h o – Object height h i – Image height m – Magnification All of these values are concerning the object or image. A positive value indicates the image (or object) is upright and a negative is inverted. The magnification value is analogous to a percentage: less than 1 is a shrunken image, greater than 1 is enlarged
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Problem #1 A concave mirror has a radius of curvature of 12.0cm and the object is placed 9.8cm from the mirror. A.What is the focal length of the mirror? B.What is the image distance? C.Is the image: Real or Virtual, Enlarged or Reduced, Upright or Inverted? D.What is the magnification of the image? E.Draw the scenario to show the mirror, object and image as well as the principle rays. A. 6cmB. 15.5cmC. R,E,ID. -1.58
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Problem #2 A convex mirror has a focal length of 9.0cm and the object is placed 2cm from the mirror. A.What is the radius of curvature of the mirror? B.What is the image distance? C.Is the image: Real or Virtual, Enlarged or Reduced, Upright or Inverted? D.What is the magnification of the image? E.Draw the scenario to show the mirror, object and image as well as the principle rays. A. -18cmB. -1.64cmC. V,R,UD. 0.82
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