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Dynamics and Space Acceleration
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Learning Outcomes Acceleration of a vehicle between two points using appropriate relationships with initial and final velocity and time of change. Acceleration from a velocity time graph.
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Lesson 1 Define the term acceleration. Carry out an experiment to determine the acceleration of a trolley.
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Acceleration Intro Have you ever heard a phrase used to describe how quick a car is? It can do 0 – 60 in 3 seconds. This is an example of a cars acceleration
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Acceleration Name of Car Time to accelerate from 0-27m/s (s) Micra15.2 Focus12.9 Corsa19.9 Ka13.7 Smart car19.6 Mondeo13.0 Questions to consider: 1.Which car takes the shortest time to speed up to 27 m/s? 2.Which car has the fastest acceleration? Why? 3.Which car takes the longest time to speed up to 27 m/s? 4.Which car has the slowest acceleration? Why?
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Acceleration An acceleration is defined as “the change in velocity per unit time”. It is the change in velocity of a body over a certain time period.
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Acceleration Acceleration, (a), can be calculated by subtracting the initial velocity, (u), from the final velocity (v), of a body over a certain period of time, (t). a=v – u t Acceleration has the unit m/s 2 It is a vector quantity.
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Experiment to Measure Acceleration
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Results QuantityValue t 1, time to pass light gate 1 s t 2, time to pass light gate 2 s t 3, time to travel between light gates s d, card length m u, initial velocity (d / t 1 ) m/s u, final velocity (d / t 2 ) m/s a, acceleration (v – u / t 3 ) m/s 2
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Lesson 2 Carry out calculations for acceleration using the equation a = v – u. t State that deceleration is a negative acceleration. Calculate acceleration from a slope on a velocity-time graph.
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Example 1 a = ? v = 27 m/s u = 0 m/s t = 19.9 s
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Example 2 a = 20 m/s 2 v = 65 m/s u = 5 m/s t = ?
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Example 3 a = 10 m/s 2 v = ? u = 10 m/s t = 5 s
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Deceleration If a moving body has a ‘negative acceleration’ then it is decelerating. In other words it is slowing down.
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Example a = ? v = 0 m/s u = 25 m/s t = 5 s
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v-t graph example Using the v-t graph below for the motion of a car find: a)The initial acceleration b)The final acceleration a)a = v – u t = 10-0 4 = 2.5 m/s 2 b)a = v – u t = 0-10_ (10-8) = - 5 m/s 2 [note –ve sign for deceleration]
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Velocity-Time Graphs Questions on displacement and acceleration
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2011
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2008
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2009
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2000, Qu: 21
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2003 Qu: 21
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2007 Qu: 21
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2010 Qu: 21
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Summary Acceleration You should now be able to do the following: Determine the acceleration of a vehicle between two points using a = v-u. t Calculate the acceleration of a body from a slope on a velocity-time graph.
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