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Gottfried Wilhelm von Leibniz 1646 – 1716 Gottfried Wilhelm von Leibniz 1646 – 1716 Gottfried Leibniz was a German mathematician who developed the present.

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Presentation on theme: "Gottfried Wilhelm von Leibniz 1646 – 1716 Gottfried Wilhelm von Leibniz 1646 – 1716 Gottfried Leibniz was a German mathematician who developed the present."— Presentation transcript:

1 Gottfried Wilhelm von Leibniz 1646 – 1716 Gottfried Wilhelm von Leibniz 1646 – 1716 Gottfried Leibniz was a German mathematician who developed the present day notation for the differential and integral calculus though he never thought of the derivative as a limit. His philosophy is also important and he invented an early calculating machine.

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4 Example: Find the function whose derivative is and whose graph passes through. Notice that we had to have initial values to determine the value of C.

5 The process of finding the original function from the derivative is so important that it has a name: You will hear much more about antiderivatives in the future. This section is just an introduction. The process of finding an antiderivative is antidifferentiation.

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7 Integration Symbol Integrand Variable of integration (dummy variable) Antiderivative Constant of Integration

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9 Since acceleration is the derivative of velocity, velocity must be the antiderivative of acceleration. Example: Find the velocity and position equations for a downward acceleration of a m/sec 2 and an initial velocity of v 0 m/sec.

10 Since acceleration is the derivative of velocity, velocity must be the antiderivative of acceleration. Example: Find the velocity and position equations for a downward acceleration of a m/sec 2 and an initial velocity of v 0 m/sec. Since velocity is the derivative of position, position must be the antiderivative of velocity. The power rule in reverse: Increase the exponent by one and multiply by the reciprocal of the new exponent.

11 Since acceleration is the derivative of velocity, velocity must be the antiderivative of acceleration. Example: Find the velocity and position equations for a downward acceleration of a m/sec 2 and an initial velocity of v 0 m/sec. The initial position is s(0) = s 0.

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13 Examples: 1)


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