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Chapter 1.8 Absolute Value and Inequalities. Recall from Chapter R that the absolute value of a number a, written |a|, gives the distance from a to 0.

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Presentation on theme: "Chapter 1.8 Absolute Value and Inequalities. Recall from Chapter R that the absolute value of a number a, written |a|, gives the distance from a to 0."— Presentation transcript:

1 Chapter 1.8 Absolute Value and Inequalities

2 Recall from Chapter R that the absolute value of a number a, written |a|, gives the distance from a to 0 on a number line. By this definition, the equation |x| = 3 can be solved by finding all real numbers at a distance of 3 units from 0.

3 |x| = 3 Two numbers satisfy this equation, 3 and -3, so the solution set is {-3, 3}. | -3 | 0 | 3 Distance is less than 3. Distance is 3. Distance is 3. Distance is greater than 3. Distance is greater than 3.

4 Similarly |x| < 3 is satisfied by all real numbers whose distances from 0 are less than 3, that is, the interval -3<x<3 or (-3,3).

5 Properties of Absolute Value

6 Example 1 Solving Absolute Value Equations

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8 Example 2 Solving Absolute Value Inequalities

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10 Example 3 Solving Absolute Value Inequalities Requiring a Transformation

11 Example 4 Solving Absolute Value Equations and Inequalities

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13 Absolute Value Models for Distance and Tolerance Recall from Selection R.2 that is a and b represent two real numbers, then the absolute value of their difference, either |a - b| or |b – a|, represent the distance between them. This fact is used to write absolute value equations or inequalities to express distance.

14 Example 5 Using Absolute Value Inequaliteis to Describe Distances Write each statement using an absolute value inequality. (a) k is no less than 5 units from 8

15 Example 5 Using Absolute Value Inequaliteis to Describe Distances Write each statement using an absolute value inequality. (b) n is within.001 unit of 6

16 Example 6 Using Absolute Value to Model Tolerance Suppose y = 2x + 1 and we want y to be within.01 unit of 4. For what values of x will this be true? |y – 4| <.01 |2x + 1 – 4| <.01

17 Homework Section 1.8 # 1 - 82


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