1. WARMUP (3,2)X=3 All Real Numbers y ≤ 2 Reflected over x Stretched vertically, right 3, up 2 (2,0) (4,0) (0, -16)

3. x4 x 4 x2x2 4x 16 No matter which method you choose, put original equation into y1 and your answer into y2 and check to be sure the tables match!!!

4. Finally, a FOURTH way to do this, using the calculator. 1)Put the equation you are given into the calculator, in y= 2)Look at the table, and pick a few points. Preferably, pick at least one point on either side of the vertex. 3)Go to STAT Edit, and enter the points you chose into L1 (x-values) and L2 (y-values). 4)Go to STAT Calc 5 and get your equation. 5)As always, put both equations into y= and make sure that the tables match.

5. What does the graph look like? We know that the vertex is at (2,4) because it’s in vertex form. We know that the graph opens up, because it’s positive So, the graph looks roughly like this:

6. x-2 x x2x2 -2x 4 SAME ANSWER EVERY TIME!

7. x x x2x2 -x 1

8. This is already in standard form Put it into y=, and use 2 nd Trace 4 to find the vertex. The vertex is at (3,2)

9. Once again, the vertex is at (3,2)

12. Find Parabola Fitting over Points  Estimation/Modeling Quadratic Regression and Calculations

13. 1-75 4-7

14. 2 8

15. -17.07110.73-3 Enter equation in y= and look at the table for x = 6. OR – simply plug 6 into the equation by hand. Either way, we get that the ball will be around 47 feet off the ground after 6 seconds.

16. 12-2336 136221

17. -.116 To find x = 8.5 on the graph, go to 2 nd Window, and change TblStart= to 8.5. 2 nd Graph will show you 7.275

18. -.116 You can also use the STO button to find this. Type 8.5, STO, x. Then type in the equation (not in y=) to get your answer. Again, you will get 7.275