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Published byAdelia McDaniel Modified over 9 years ago
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Getting Started A few idle thoughts
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The Uniqueness of Astronomy Among other things, unfamiliar scales One consequence: non-standard units (partly also for historical reasons) - distances in light-years, parsecs, Mpc - times in years, My, Gy rather than seconds - velocities (often) in km/s - masses and luminosities in solar units - wavelength scales from metres to nm - energies in eV / GeV / TeV (cf particle physics) - Or even less standard! (c = G = 1 units! Masses in km!)
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Dimensional analysis -Thinking about g g ~ 10 m/sec 2 But why seconds 2 ? It could equivalently be written 36 km/h / sec (i.e. we pick up 36 km/h of speed every second we fall. After 2.7 seconds, we are already falling at highway speed! [100 km/h]) Or write 36 km/sec /h (which tells us that we will be moving at 36 km/s after just one hour of acceleration at a modest 1-g. There’s no need to accelerate fantastically quickly if we can find a way to provide a steady, sustained acceleration)
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More on dimension Think about the Hubble constant, H o (not strictly a constant: it changes with time, but has a unique value over all space at any given moment. The word ‘parameter’ would be better) If H o = 75 km/sec/Mpc, the implication is that a galaxy 1 Mpc away has a recession velocity of 75 km/sec; an object at twice that distance has twice that velocity; etc - units of inverse time: the ‘expansion age’ of the universe
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More on H o The dimensionality of H o is velocity/distance = [L/T] / [L] = 1/[T] Noting that 1 Mpc = 3.1 x 10 19 km, we can ‘cancel out’ the kms and get H o = (75 / 3.1 x 10 19 ) sec -1 So 1/H o = 4.1 x 10 17 sec ~ 13 billion years This is the ‘Hubble time’, or (in the absence of any deceleration or acceleration) the time that has elapsed since the universal expansion began: that is, the ‘age of the universe’
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Periods for Satellites For an orbiting satellite P will be some function of G, M, and R (M = mass of body being orbited; R = distance; G = G!) Write P = G α M β R γ and solve for α,β,γ by dimensional analysis. [P], the dimensionality of P, is time [T]. [R], the dimensionality of R, is length [L]. [G], the dimensionality of G, is [L] 3 [M] -1 [T] -2
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[P] = [L 3α ] [M -α ][T -2α ] [M β ] [L γ ] = [T] Look at T to deduce -2α = 1, so α = -1/2 Look at M to deduce β-α = 0so β = α = -1/2 Look at L to deduce 3α + γ = 0 so γ = -3α = 3/2 Consequently P depends on G -1/2 M -1/2 R 3/2 so P goes like 1/ ( √G √ (M/R 3 ) ) or, in short, P goes like 1 / sqrt (G x density) In other words, the ‘dynamical time scale’ is set by “1 over root-G-rho” SO: if we skim the surface of a tiny rocky asteroid that has the same mean density as the Earth, it will take the same period (~90 min) as a low-altitude satellite like the ISS orbiting the Earth. (Obviously it moves much more slowly around the asteroid, but the periods are the same!) Note: the larger G is, the shorter the timescale (makes sense). Likewise, the denser the object, the shorter the period.
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Angular measure - radian: definition and implications - the parsec by definition: review this! - simple conversions 1 radian ~ 57.3 degrees 1 radian ~ 2 x 10 5 seconds of arc
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Angular size / solid angle - steradians
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The Whole Sky = 4 π steradians = 4 π (57.3) 2 square degrees = 41,259 square degrees ~ 160,000 full moons
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Surveys Palomar Sky Survey: (Schmidt telescope) plates are 6.6 degrees on a side full sky survey requires ~1000 plates or more
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Largest angular sizes studied? The whole sphere, for things like large-scale structure in cosmology (structure in the microwave background) A large swath across the sky, for something like the Milky Way But for most objects, the angular size is at most a couple of degrees (e.g. M31, the Andromeda galaxy) and usually very much less
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Various image sizes
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Small Field of View The Hubble Telescope ACS (Advanced Camera for Surveys) has a field which is 202 x 202 arcsec I radian is ~ 2 x 10 5 arcsec, so the ACS has a field of 0.001 x 0.001 radians 0.001 radians is the angle subtended by a 1 mm object (a grain of rice) a metre away – that is, at arm’s length The ACS area is about 10 -6 steradians, so a full-sky survey would require ~ 13 million pointings in each filter
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One Such Microscopic Pointing: The HST Ultra-Deep Field
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