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Warm Up 1. 203 cm to meters 2. 234 m to km 3. 8,009 g to kg 4. 0.987 L to mL 5. 0.97 kg to mg.

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Presentation on theme: "Warm Up 1. 203 cm to meters 2. 234 m to km 3. 8,009 g to kg 4. 0.987 L to mL 5. 0.97 kg to mg."— Presentation transcript:

1 Warm Up 1. 203 cm to meters 2. 234 m to km 3. 8,009 g to kg 4. 0.987 L to mL 5. 0.97 kg to mg

2 Introduction to Motion  Objective: Know the difference between distance and displacement and speed and velocity

3 What is motion?  Motion: change of the position of an object with respect to time Ouch.

4  Definition: Total length traveled  Unit: meter  What distance did the turtle cover?

5  Definition: change in the position of an object from its beginning point  Unit: meter  Formula: Δx = x f -x i ΔxΔx xixi xfxf

6  Distance = total length traveled  Displacement = change in position from starting location  What total distance did the turtle cover?  What was his displacement?

7 Displacement  Positive displacement: moving up or forward  Negative displacement: moving down or backward

8 Positive or Negative displacement? 2 m 4 m 2 m 4 m + + - -

9 Speed  Definition: rate of change in distance with respect to time  Unit: meter/second or m/s  Formula: speed = distance/time

10  Definition: rate of change in displacement with respect to time  Unit: meter/second or m/s  Formula: v avg = x f – x i = displacement = ∆x t f – t i time ∆t Average Velocity

11  Can be positive or negative  Depends on sign of displacement  Positive velocity = moving forward  Negative velocity = moving backward

12 Velocity vs. Speed  Velocity is a VECTOR quantity, which means it describes motion with both magnitude and direction  Rate of change of DISPLACEMENT with respect to time  Speed is a SCALAR quantity, which means it has no direction, only magnitude  Rate of change of DISTANCE with respect to time  Video (Vector) Video (Vector)

13 The GUESS Method  During football practice, Martin and Johnny run 2.7 km eastward in 25 minutes. How fast were they running? G iven U nknown E quation S ubstitute S olve 2.7 miles = x, 25 minutes = t velocity v = ∆x/∆t v = 2.7 miles/25 minutes v = 0.108 km/min eastward

14 Homework  Worksheet p. 62 #2, 5, 6, 26-31  Checkout textbooks

15 Lab/Activity  Intro to Motion Detectors

16 Exit Question (use GUESS)  A turtle walks 2.0 meters forward and 1.0 m backward in 10 minutes. What is the Turtle’s velocity in m/s?  G  U  E  S


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