1. Inference with Computer Printouts

2. Leaning Tower of Pisa Find a 90% confidence interval. Year75777880818283848587 Lean642656667688696698713717725757

3. Coefficie nts Standard Errort StatP-value Lower 95% Upper 95% Intercept-42.409132.95436-1.28690.234113-118.40233.5838 Year9.0924760.4054522.425661.65E-088.15750810.02745 Leaning Tower - Excell Regression Statistics Multiple R0.99214 R Square0.984342 Adjusted R Square0.982384 Standard Error4.579967 Observations10

4. Predictor Coef SE Coef T P Constant -42.41 32.95 -1.29 0.234 Year 9.0925 0.4054 22.43 0.000 S = 4.57997 R-Sq = 98.4% R-Sq(adj) = 98.2% Leaning Tower - Minitab

5. The following data is based on x (height in inches) and y (weight in lb) based on a sample of 10. Find a 90% confidence interval to estimate the slope. Predictor Coef SE Coef T P Constant -104.46 43.75 -2.39 0.044 Height 3.9527 0.6580 6.01 0.000 S = 7.16009 R-Sq = 81.9% R-Sq(adj) = 79.6%

6. The following data is based on x (height) and y (weight). Is there a relationship? Predictor Coef SE Coef T P Constant -104.46 43.75 -2.39 0.044 Height 3.9527 0.6580 6.01 0.000 S = 7.16009 R-Sq = 81.9% R-Sq(adj) = 79.6%

7. The following is the regression analysis of y = maximum benchpress (MAX) and x = # of 60-pound Bench Presses (BP). Find a 95% CI. Use n = 10 PredictorCoefSE CoefTP Constant63.5371.95632.480.000 BP1.49110.159.960.000 R-Sq = 64.3%

8. The following is the regression analysis of y = maximum benchpress (MAX) and x = # of 60-pound Bench Presses (BP). Are they related? Use n = 10 PredictorCoefSE CoefTP Constant63.5371.95632.480.000 BP1.49110.159.960.000 R-Sq = 64.3%

9. The following shows they car weight (in lb) and the mileage (mpg) of 25 different models. PredictorCoefSE CoefTP Constant45.6562.60317.540.000 BP-0.00520.00062-8.330.000 R-Sq = 64.3% 1.Give the prediction equation. 2.State & interpret the slope & y-int

10. The following shows they car weight (in lb) and the mileage (mpg) of 25 different models. PredictorCoefSE CoefTP Constant45.6562.60317.540.000 BP-0.00520.00062-8.330.000 R-Sq = 64.3% 1.What is the correlation coefficient? 2.Estimate 

11. Homework Worksheet