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E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 1 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Licensed Electrical &

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Presentation on theme: "E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 1 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Licensed Electrical &"— Presentation transcript:

1 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 1 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Engineering 25 Tutorial: Areal Moment of Inertia

2 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 2 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Parallogram I C  Determine the moment of inertia for the parallelogram about the y’ axis, which passes through the centroid C of the area in terms of a, b, and θ.

3 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 3 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

4 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 4 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

5 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 5 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

6 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 6 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

7 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 7 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

8 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 8 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics MuPAD WorkBook

9 E ENGR36_Tutorial_Areal_Moment_of_Inertia.pptx 9 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics MATLAB Results >> Q = 53 Q = 53 >> a = 7 a = 7 >> b = 11 b = 11 >> e = a*cosd(Q) e = 4.2127 >> h = a*sind(Q) h = 5.5904 >> ICy = b*h*(b^2+e^2)/12 ICy = 711.0192


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