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Section Optimization Competition. Baseline model C-section –9 in. web, 3 in. flange, ½ in. lips t=0.068 in. –f y = 50 ksi –A = 1.088 in 2 –M y = 151 kip-in.

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Presentation on theme: "Section Optimization Competition. Baseline model C-section –9 in. web, 3 in. flange, ½ in. lips t=0.068 in. –f y = 50 ksi –A = 1.088 in 2 –M y = 151 kip-in."— Presentation transcript:

1 Section Optimization Competition

2 Baseline model C-section –9 in. web, 3 in. flange, ½ in. lips t=0.068 in. –f y = 50 ksi –A = 1.088 in 2 –M y = 151 kip-in. Loading and conditions –pure flexural loading (beam) – pin supports –braced at 96 in.

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5 Baseline response

6 Ben Schafer entrant A = 1.088 in 2 My = Mcr = Mcrd = Mcre (96 in.) = Mne = Mn = Mnd = Mn = Yes 151 kip-in. 136 kip-in. 95 kip-in. 140 kip-in. 118 kip-in. 105 kip-in. 99 kip-in. Comment: 9x3x0.5 C-section – nothing fancy

7 Competition You (and your computer partners) have until xxx pm to develop the best beam you can. Key constraints –A must be within 1% of 1.088 in 2 –Mcre is taken at 96 in., fy=50 ksi When you have a beam you would like to enter on the big board, let me know. Raise your hands or speak up if you have any questions...

8 XXXX entrant A = 1.088 in 2 My = Mcr = Mcrd = Mcre (96 in.) = Mne = Mn = Mnd = Mn = XXYesXX xxx kip-in. xx kip-in. Comment: XXXX

9 XXXX entrant A = 1.088 in 2 My = Mcr = Mcrd = Mcre (96 in.) = Mne = Mn = Mnd = Mn = XXYesXX xxx kip-in. xx kip-in. Comment: XXXX

10 XXXX entrant A = 1.088 in 2 My = Mcr = Mcrd = Mcre (96 in.) = Mne = Mn = Mnd = Mn = XXYesXX xxx kip-in. xx kip-in. Comment: XXXX

11 XXXX entrant A = 1.088 in 2 My = Mcr = Mcrd = Mcre (96 in.) = Mne = Mn = Mnd = Mn = XXYesXX xxx kip-in. xx kip-in. Comment: XXXX

12 XXXX entrant A = 1.088 in 2 My = Mcr = Mcrd = Mcre (96 in.) = Mne = Mn = Mnd = Mn = XXYesXX xxx kip-in. xx kip-in. Comment: XXXX


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