1. QZ11 Lesson 23 Q1) Let us label the answers from 1 (=1) to 15 (=z) (going from left to right) then the correct answer is: A. 6, 9, 11, 3, 12, 8, 4 B. 7, 9, 8, 2, 11, 8, 4 C. 6, 9, 11, 1, 11, 8, 4 D. 7, 9, 8, 2, 14, 8, 4 E.NONE of the above

2. QZ11 Lesson 23 Q2) Under the null hypothesis of (independence) the expected (E) number of low birth weight babies born to smoking mothers is 189* (74/189)*(59/189) =23.1 A.TRUE B.FALSE

3. QZ11 Lesson 23 Q3) Now concentrate on cell (2,2) 30 is the observed (O) number of low birth weight babies born to smoking mothers 30 out of 189 total pregnancies. What is TRUE about the rest of the numbers in cell (2,2)? A. 15.87=Total%=30/189 B. 50.85=Col%=30/59 C. 40.54=Row%=30/74 D. ALL OF THE ABOVE ARE TRUE

4. QZ11 Lesson 23 Q4) The (2,2) cell Chi Square contribution is calculated by using the observed (O=30) and expected (E=23.1) by the following formula A. (E-O) 2 / O B. (E-O) / E C. (O-E) 2 / E D. (O-E) / E E.NONE OF THE ABOVE

5. QZ11 Lesson 23 Chi Square Q5) The Pearson overall Chi Square statistic for testing the H o null hypothesis of independence is calculated by summing the cell Chi squares contributions with (2-1)*(3- 1)=2 degrees of freedom (d.f.) for each cell and the conclusion is A.TRUE and NOT reject H o B.FALSE and reject H o C.TRUE and reject H o. D.FALSE and reject H o E.NONE OF THE ABOVE