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Published byMaurice Foster Modified over 9 years ago
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TS / AP / SEANCE 1 LES REACTIONS D’OXYDOREDUCTION
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Cu 2+ + 2 e - = Cu 2 H + + 2 e - = H 2 Al 3+ + 3 e - = Al Ag + +e - = Ag I 2 + 2 e - = 2 I -
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O 2 + 4 H + + 4 e - =2 H 2 O Cl 2 + 2e - = 2Cl - H 2 O 2 + 2H + + 2e - = 2H 2 O
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S 2 O 8 2- + 2e - = 2SO 4 2- S 4 O 6 2- + 2e - = 2S 2 O 3 2- BrO 4 - +2 H + + 2e - = BrO 3 - + H 2 O
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2 HClO + 2H + + 2 e - = Cl 2 + 2 H 2 O MnO 4 - + 8H + + 5 e - = Mn 2+ + 4H 2 O Cr 2 O 7 2- + 14 H + + 6e - = 2Cr 3+ + 7H 2 O
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(2H + + 2e - = H 2 ) (Al = Al 3+ + 3e - ) 6 H + + 2 Al 3H 2 + 2 Al 3+ x 3 x2
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(2H 2 O = O 2 + 4H + + 4e - ) x 3 Cr 2 O 7 2- + 14 H + + 6e - = 2Cr 3+ + 7H 2 O x 2 2Cr 2 O 7 2- + 28H + + 6H 2 O 4Cr 3+ + 14H 2 O +3O 2 + 12H + 2 Cr 2 O 7 2- + 16 H + 4Cr 3+ +8 H 2 O +3O 2
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2S 2 O 3 2- = S 4 O 6 2- + 2e - Cl 2 + 2e - = 2Cl - 2S 2 O 3 2- + Cl 2 S 4 O 6 2- + 2Cl -
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