1. Group members: Boya Bill Frank Laura

2. Get into your groups!!(ELS groups in Miss.Murphy ’s class) Review Unit 1 ： MEASUREMENT Have a groups competition Checking answers AGENDA

3.  Body is a “natural ruler” Can you gave us some examples.(for example your hands is about 18cm)  Do you have any examples around you.(for example the thickness of iPhone is 1cm) BRAIN STORM

4. Imperial unit AbbreviationreferentRelationship Between Unit Inchin.Thumb length Footft.Foot length1ft. =12 in. Yardyd.Arm span1yd.=3ft. 1yd.=36in. Milemi.Distance walked in 20 min 1mi.=1760yd. 1mi.=5280ft. IMPERIAL UNIT

5. SI VS. IMPERIAL SI Units to Imperial UnitsImperial Units to SI Units 1mm=4/100in.1in.=2.5cm 1cm=4/101ft=30cm 1ft=0.3m 1m=39in. 1m=3*1/4ft. 1yd=90cm 1yd=0.9m 1km=6/10mi.1mi.=1.6km

6. Convert 3 feet into meters  If we put a 1-meter ruler next to a 1- foot ruler, they would look like this:  If you then looked more closely, you would see that the 1-foot ruler came to exactly 0.3048 on the meter ruler: EXAMPLE 1

7.  So, the conversion for feet to meters is: 1 ft = 0.3048 meters  To convert feet to meters, multiply by 0.3048  Let me show you why this works: to find what 3 feet would be in meters, we could put three 1 foot rulers next to each other like this: EXAMPLE 1

8.  So, you can see that 3 feet = 3 × 0.3048 meters = 0.9144 meters  So, 3 ft. = 0.9144 m EXAMPLE 1

9. Let have a competition!! QUESTION (on text book page 22) 25mm to the nearest inch 2.5m to the nearest foot 10m to the nearest yard 150km to the nearest mile EXERCISE

10.  Area is the two-dimensional (2-D) size of a surface. Consider the area that your notebook is covering on the surface of your desk  Surface area (SA) of a solid is the total area of the exposed surfaces of a three- dimensional (3-D) object. SURFACE AREAS

11. Right Pyramid Atriangle = 1/2bs Abase = b 2 SA = 2bs + b 2 SURFACE AREA FORMULAS

12. Rectangular SA = 2(hl + lw + hw) SURFACE AREA FORMULAS

15. VOLUME FORMULAS  Pyramid  Volume = (B × h)/3 B is the area of the base h is the height

16.  Cone  Volume = (pi × r 2 × h)/3 pi = 3.14 r is the radius h is the height VOLUME FORMULAS

17.  Sphere  Volume = (4 × pi × r 3 )/3 pi = 3.14 r is the radius VOLUME FORMULAS

18.  Rectangular  Volume = l × w × h l is the length w is the width h is the height VOLUME FORMULAS

19.  Cylinder  Volume = π × r 2 × h pi = 3.14 h is the height r is the radius VOLUME FORMULAS

20.  Determine the surface area of the composite object at the right to the nearest square meter. PROBLEM SOLUTION A B C D

21. 8*8+AB*AB=10*10 AB=6m CB=AB-2m=4m CD*CD=4*4+5*5 CD=6.4m S composite object = 3*6.4+2*3+3*10+3*(5+8)+5*4*1/2*2+8*6*1/2*2 =19.2+6+30+39+20+48 =162.2 square meter ANSWER

22. Determine the volume of the composite object at the right to the nearest cubic meter. ABOUT VOLUME A B C D

23. ANSWER 8*8+AB*AB=10*10 AB=6m CB=AB-2m=4m CD*CD=4*4+5*5 CD=6.4m V composite object = 6*8*3*1/2+4*5*3*1/2 =72+30 =102 cubic meter

24. Have a group competition