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Published byAmi Gray Modified over 8 years ago
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Monohybrid Crosses
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RR
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R r r r RR or Rr Punnett Square: F 1 : RR r r Rr 100% Rr (heterozygous dominant)
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Rr r r Rr rr F1:F1: 50% homozygous recessive (rr) 50% heterozygous dominant (Rr) R R r r RR Rr rr Rr
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RR r r Therefore, all would be a round seed coat, 100% heterozygous dominant (Rr) Rr r r Rr rr Rr Therefore, 50% would be round, heterozygous dominant 50% would be wrinkled, homozygous recessive
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T = tall t = short P: Tall x short** Tall can be TT or Tt Case 1: P = TT x tt F 1: TT t t Tt Therefore, 100% would be tall (heterozygous dominant) Case 2: P = Tt x tt F 1: Tt t t Tttt Tt Therefore, 50% would be Tall (heterozygous dominant) 50% would be short (homozygous recessive)
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Homework #1, 3-12 (p.207) #1, 2, 4, 6, 8, 10 (practice problems – p. 212) # 8 (learning check – p. 212) Complete Spongebob Genetics worksheet
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