Presentation is loading. Please wait.

Presentation is loading. Please wait.

Discrete Probability Distributions Chapter 4. § 4.3 More Discrete Probability Distributions.

Similar presentations


Presentation on theme: "Discrete Probability Distributions Chapter 4. § 4.3 More Discrete Probability Distributions."— Presentation transcript:

1 Discrete Probability Distributions Chapter 4

2 § 4.3 More Discrete Probability Distributions

3 Larson & Farber, Elementary Statistics: Picturing the World, 3e 3 Geometric Distribution A geometric distribution is a discrete probability distribution of a random variable x that satisfies the following conditions. 1. A trial is repeated until a success occurs. 2. The repeated trials are independent of each other. 3.The probability of a success p is constant for each trial. The probability that the first success will occur on trial x is P (x) = p(q) x – 1, where q = 1 – p.

4 Larson & Farber, Elementary Statistics: Picturing the World, 3e 4 Geometric Distribution Example : A fast food chain puts a winning game piece on every fifth package of French fries. Find the probability that you will win a prize, a.) with your third purchase of French fries, b.) with your third or fourth purchase of French fries. p = 0.20q = 0.80 = (0.2)(0.8) 2 = (0.2)(0.64) = 0.128 a.) x = 3 P (3) = (0.2)(0.8) 3 – 1  0.230 b.) x = 3, 4 P (3 or 4) = P (3) + P (4)  0.128 + 0.102

5 Larson & Farber, Elementary Statistics: Picturing the World, 3e 5 Homework Read and take notes on section 3 (pages 198-201) Pages 202-204, 1-4, 15-18

6 Larson & Farber, Elementary Statistics: Picturing the World, 3e 6 Homework 1-4, 15-18 10.032 20.25 30.0562 40.0340 15a 0.0818 b 0.4686c 0.5314 16a 0.2483b 0.7893c 0.2107 17a 0.0091b 0.0297c 0.9044 18a 0.1055b 0.5781c 0.3164

7 Larson & Farber, Elementary Statistics: Picturing the World, 3e 7 Geometric Distribution Example : A fast food chain puts a winning game piece on every fifth package of French fries. Find the probability that you will win a prize, a.) with your third purchase of French fries, b.) with your third or fourth purchase of French fries. p = 0.20q = 0.80 = (0.2)(0.8) 2 = (0.2)(0.64) = 0.128 a.) x = 3 P (3) = (0.2)(0.8) 3 – 1  0.230 b.) x = 3, 4 P (3 or 4) = P (3) + P (4)  0.128 + 0.102


Download ppt "Discrete Probability Distributions Chapter 4. § 4.3 More Discrete Probability Distributions."

Similar presentations


Ads by Google