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Circles.

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Presentation on theme: "Circles."— Presentation transcript:

1 Circles

2 Radius Diameter

3 Tangent (major) Segment Chord (minor) Segment Arc

4 Circumference of a circle =
or r D p 2

5 Area of a circle = r2

6

7

8 Angles held up by the diameter are called “Angles in the semi-circle” and are all 900

9 Isosceles triangles are formed by two radii
. . The angle in a semicircle is 90° Isosceles triangles are formed by two radii . . Chord Any chord bisector is a diameter Radius Tangent Tangent and Radius meet at 90° 90°

10 Angles in the same segment are equal
x

11 x 2x Angles from chord to centre are twice the size of angles from chord to circumference

12 The angle at the centre is 1800 , so the angle at the circumference is half that - 900

13 Opposite angles in cyclic quadrilateral add up to 1800 (supplementary)
680 . c a b = 1120 opposite angle of a cyclic quadrilateral

14 Opposite angles in cyclic quadrilateral add up to 1800 (supplementary)
680 . c a b = 1120 opposite angle of a cyclic quadrilateral Adjacent angles in cyclic trapezium are equal - angles subtended by an arc.

15 a 420 b . d c Find the missing angles a, b, c and d

16 . d = 840 angle at the centre is twice the angle at the circumference
= 420 angle in the same segment 420 b = 420 angle in the same segment . d c

17 770 . c a b Find the missing angles a, b, and c

18 . c a = 770 adjacent angle of a cyclic trapezium b
= 1030 adjacent angle of a cyclic trapezium, or opposite angle of a cyclic quadrilateral b = 1030 opposite angle of a cyclic quadrilateral

19 For the following circles, where O is the centre of the circle, find the missing angles
870 1350 c . . . e o o d o a b 470 480 i k 920 . . f 580 h o l o j 390 g m 1100

20 For the following circles, where O is the centre of the circle, find the missing angles
870 1350 . . . d = 900 e = 960 d o o o e a a =930 b =450 b 470 480 k=320 f h=1220 i=900 920 . f = 390 . 580 i k h l o j o l=460 j=320 390 g = 310 m g m=460 310 1100

21 Two tangents drawn from an outside point are always equal in length,
so creating an isosceles situation with two congruent right-angled triangles

22 Reminder of “segment” (major) Segment (minor) Segment

23 The angle in the opposite segment
The angle between chord and tangent The angle between a chord and a tangent = the angle in the opposite segment

24 Two tangents drawn from an outside point are always equal in length,
so creating an isosceles situation with two congruent right-angled triangles The angle in the opposite segment The angle between chord and tangent The angle between a chord and a tangent = the angle in the opposite segment m m

25 Angle between tangent and radius is a right angle
900 B Angle at the centre is twice the angle at the circumference 600 A 850 1700 100 O 250 The angle between a chord and a tangent = the angle in the opposite segment 950 C E 250 In kite BEDO, BED = 360-known angles =100 D Opposite angles of a cyclic quad are supplementary Find each of the following angles OBE BOD BED BCD CAB


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