1. CRAZY CORE SKITTLES

2. The Purpose  It is stated that the Crazy Cores Skittles Company have 56.7 grams of Skittles in each bag. Is this accurate?  The population of interest is a sample size of 15 regular sized Crazy Core Skittles bags from a private supplier.

3. Sneaky Lurking Variables  The Skittles weighed in the experiment all came from one supplier, so there is a possibility that the skittles all came from the same batch from manufacturer.  The supplier from which produced the skittles does not have a license to sell, so there can be some doubt if the goods he/she were selling are standard.

4. More Luring Variables  The efficiency of the scale is questioned due to the fact that I carried it around in my purse.  My sample size is only 15, while it is large enough to perform a one sample T test, if there was a larger sample it would be able to speak for a larger amount of skittles.

5. Procedure 1. Contact the skittles dealer. 2. Weigh each bag of skittles and record the weight.

6. Numbers, Graphs, and Data  Skittles Weight  60.1, 59.01, 59.3, 58.4,58.4, 59.5,58.6,62.1,61.9,57.8, 59.4,60.9,58.24,57.6,56.2

7. More Numbers  Five number Summary  Mean= 59.16 grams  Minimum= 56.2 grams  Maximum= 62.1 grams  Q 1 = 58.24 grams  Q 3 =60.1 grams  S x = 1.59  Medium=59.01 since the mean is greater than the medium, the graph is slightly skewed to the right.

8. Hypothesis  H o : In a sample size of 15 bags of Crazy Core Skittles, the mean weight is 56.7 grams. X= 56.7grams  H a : In a sample size of 15 bags of Crazy Core Skittles, the mean weight is more than 56.7 grams X>56.7 grams

9. Inference Procedure  The significance level that the data will be tested is at.05%.  The sample size is fifteen 56.7 gram Crazy Core Skittle bags.  A one sample T test will be used since the population mean is unknown.

10. Conditions  Not an SRS: PROCEED With Caution  Sample size shows little to no skewness and no extreme outliers.

11. Box Plot

12. Formulas  T test  T= x- µ s/n df= n-1  X=59.13 µ=56.7 S=1.59 n=15  59.13-56.7 =5.979 T=5.979 P value= 1.63e -5 1.59/15

13. What Does The Numbers Mean? Conclusion  The P- Value was 1.63e-5 at an Alpha level of.05%. This is significant evidence to reject the null Hypothesis.  Therefore, In a sample size of 15 bags of Crazy Core Skittles, the mean weight is more than 56.7 grams. X>56.7 grams

14. Confidence Interval Test Confidence Interval for : X=59.133 T*=5.979 n=15 S=1.59 59.133+/-5.979 15-1 (1.59/√15= 58.28, 60.047

15. Confidence Conclusion  According to the Confidence Interval test, I am 95% confident that the mean weight of Crazy Core Skittles bags lays between 58.28 grams and 60.047 grams. This supports my rejection of my null hypothesis.

16. Reflection  My project shows me that in a population of 15 Crazy Core Skittles bags, the mean weight is more than what is stated on the bag.  Some of the weakness of the project were that the data did not come from an SRS.