Download presentation
Presentation is loading. Please wait.
Published byEdgar Hopkins Modified over 8 years ago
1
Starter Draw a right angled triangle, where the two shorter sides are 7cm and 13cm, and measure the hypotenuse 7cm 13cm ?
2
Right-angled triangles
3
Using just the sides:Using sides and angles: Right-angled triangles
4
Using just the sides: Pythagoras’ theorem Using sides and angles: Right-angled triangles
5
Using just the sides: Pythagoras’ theorem Using sides and angles: Trigonometry Right-angled triangles
6
Using just the sides: Pythagoras’ theorem The theorem Using sides and angles: Trigonometry Right-angled triangles
7
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Using sides and angles: Trigonometry Right-angled triangles
8
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Using sides and angles: Trigonometry Right-angled triangles
9
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Pythagoras in 3-D Using sides and angles: Trigonometry Right-angled triangles
10
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Pythagoras in 3-D Pythagoras and the circle Using sides and angles: Trigonometry Right-angled triangles
11
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Pythagoras in 3-D Pythagoras and the circle Using sides and angles: Trigonometry Sine, cosine and tangent Right-angled triangles
12
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Pythagoras in 3-D Pythagoras and the circle Using sides and angles: Trigonometry Sine, cosine and tangent Finding an angle Right-angled triangles
13
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Pythagoras in 3-D Pythagoras and the circle Using sides and angles: Trigonometry Sine, cosine and tangent Finding an angle Finding a side Right-angled triangles
14
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Pythagoras in 3-D Pythagoras and the circle Using sides and angles: Trigonometry Sine, cosine and tangent Finding an angle Finding a side Looking at the graphs Right-angled triangles
15
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Pythagoras in 3-D Pythagoras and the circle Using sides and angles: Trigonometry Sine, cosine and tangent Finding an angle Finding a side Looking at the graphs Trigonometry beyond 90° Right-angled triangles
16
Using just the sides: Pythagoras’ theorem The theorem Finding the hypotenuse Finding a shorter side Pythagoras in 3-D Pythagoras and the circle Using sides and angles: Trigonometry Sine, cosine and tangent Finding an angle Finding a side Looking at the graphs Trigonometry beyond 90° Right-angled triangles
17
Pythagoras’ Theorem 5 13 12
18
5 13 12 Pythagoras’ Theorem
19
5 13 12 Pythagoras’ Theorem
20
5 13 12 Pythagoras’ Theorem
21
5 13 12 5 13 Pythagoras’ Theorem
22
5 13 12 5 13 25 Pythagoras’ Theorem
23
5 13 12 5 13 25 144 Pythagoras’ Theorem
24
5 13 12 5 13 25 144 169 Pythagoras’ Theorem
25
5 13 12 5 13 25 144 169 25 + 144 = 169 Pythagoras’ Theorem
26
a c b
27
a c b a2a2 b2b2 c2c2
28
a c b a2a2 b2b2 c2c2 a 2 + b 2 = c 2 Pythagoras’ Theorem
29
Finding the hypotenuse 4cm 3cm a 24cm 7cm b 13cm c
30
a 2 = 3 2 + 4 2 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
31
a 2 = 3 2 + 4 2 a 2 = 9 + 16 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
32
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
33
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
34
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
35
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 b 2 = 576 + 49 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
36
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 b 2 = 576 + 49 b 2 = 625 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
37
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 b 2 = 576 + 49 b 2 = 625 b = 25 cm 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
38
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 b 2 = 576 + 49 b 2 = 625 b = 25 cm c 2 = 7 2 + 13 2 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
39
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 b 2 = 576 + 49 b 2 = 625 b = 25 cm c 2 = 7 2 + 13 2 c 2 = 49 + 169 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
40
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 b 2 = 576 + 49 b 2 = 625 b = 25 cm c 2 = 7 2 + 13 2 c 2 = 49 + 169 c 2 = 218 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
41
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 b 2 = 576 + 49 b 2 = 625 b = 25 cm c 2 = 7 2 + 13 2 c 2 = 49 + 169 c 2 = 218 c = 14.8 cm (to 1 d.p.) 4cm 3cm a 24cm 7cm b 13cm c Finding the hypotenuse
42
a 2 = 3 2 + 4 2 a 2 = 9 + 16 a 2 = 25 a = 5 cm b 2 = 24 2 + 7 2 b 2 = 576 + 49 b 2 = 625 b = 25 cm c 2 = 7 2 + 13 2 c 2 = 49 + 169 c 2 = 218 c = 14.8 cm (to 1 d.p.) Exercise 15B Page 278 Questions 1-4 Finding the hypotenuse
43
Finding a shorter side a 3cm 5cm 9cm b 11cm
44
5 2 = a 2 + 3 2 a 3cm 5cm 9cm b 11cm Finding a shorter side
45
5 2 = a 2 + 3 2 25 = a 2 + 9 a 3cm 5cm 9cm b 11cm Finding a shorter side
46
5 2 = a 2 + 3 2 25 = a 2 + 9 a 2 = 16 a 3cm 5cm 9cm b 11cm Finding a shorter side
47
5 2 = a 2 + 3 2 25 = a 2 + 9 a 2 = 16 a = 4 cm a 3cm 5cm 9cm b 11cm Finding a shorter side
48
5 2 = a 2 + 3 2 25 = a 2 + 9 a 2 = 16 a = 4 cm 11 2 = b 2 + 9 2 a 3cm 5cm 9cm b 11cm Finding a shorter side
49
5 2 = a 2 + 3 2 25 = a 2 + 9 a 2 = 16 a = 4 cm 11 2 = b 2 + 9 2 121 = b 2 + 81 a 3cm 5cm 9cm b 11cm Finding a shorter side
50
5 2 = a 2 + 3 2 25 = a 2 + 9 a 2 = 16 a = 4 cm 11 2 = b 2 + 9 2 121 = b 2 + 81 b 2 = 40 a 3cm 5cm 9cm b 11cm Finding a shorter side
51
5 2 = a 2 + 3 2 25 = a 2 + 9 a 2 = 16 a = 4 cm 11 2 = b 2 + 9 2 121 = b 2 + 81 b 2 = 40 b = 6.3 cm (to 1 d.p.) a 3cm 5cm 9cm b 11cm Finding a shorter side
52
5 2 = a 2 + 3 2 25 = a 2 + 9 a 2 = 16 a = 4 cm 11 2 = b 2 + 9 2 121 = b 2 + 81 b 2 = 40 b = 6.3 cm (to 1 d.p.) Exercise 15C Page 280 Questions 1-6 Finding a shorter side
53
Pythagoras’ theorem applied twice a 6cm 5cm b 14cm
54
a 2 = 5 2 + 6 2 a 2 = 25 + 36 a 2 = 61 a = 7.8 cm a 6cm 5cm b 14cm Pythagoras’ theorem applied twice
55
a 2 = 5 2 + 6 2 a 2 = 25 + 36 a 2 = 61 a = 7.8 cm 14 2 = b 2 + 7.8 2 196 = b 2 + 61 b 2 = 135 b = 11.6 cm (to 1 d.p.) a 6cm 5cm b 14cm Pythagoras’ theorem applied twice
56
a 2 = 5 2 + 6 2 a 2 = 25 + 36 a 2 = 61 a = 7.8 cm 14 2 = b 2 + 7.8 2 196 = b 2 + 61 b 2 = 135 b = 11.6 cm (to 1 d.p.) a 6cm 5cm b 14cm Pythagoras’ theorem applied twice
57
a 2 = 5 2 + 6 2 a 2 = 25 + 36 a 2 = 61 a = 7.8 cm 14 2 = b 2 + 7.8 2 196 = b 2 + 61 b 2 = 135 b = 11.6 cm (to 1 d.p.) Exercise 15D Page 281 Question 1 Pythagoras’ theorem applied twice
58
The distance between two points What is the distance between (2, 3) and (11, -2) ?
59
The distance between two points
60
What is the distance between (2, 3) and (11, -2) ? The distance between two points
61
What is the distance between (2, 3) and (11, -2) ? The first number: How far apart are 2 & 11? The distance between two points
62
What is the distance between (2, 3) and (11, -2) ? The first number: How far apart are 2 & 11? 9 9 The distance between two points
63
What is the distance between (2, 3) and (11, -2) ? The first number: How far apart are 2 & 11? 9 The second number: How far apart are 3 & -2? 9 The distance between two points
64
What is the distance between (2, 3) and (11, -2) ? The first number: How far apart are 2 & 11? 9 The second number: How far apart are 3 & -2? 5 9 5 The distance between two points
65
x 2 = 9 2 + 5 2 x 2 = 81 + 25 x 2 = 106 x = 10.3 units What is the distance between (2, 3) and (11, -2) ? The first number: How far apart are 2 & 11? 9 The second number: How far apart are 3 & -2? 5 9 5 The distance between two points
66
x 2 = 9 2 + 5 2 x 2 = 81 + 25 x 2 = 106 x = 10.3 units What is the distance between (2, 3) and (11, -2) ? The first number: How far apart are 2 & 11? 9 The second number: How far apart are 3 & -2? 5 Exercise 15E Page 282 Questions 1-3 The distance between two points
67
Pythagoras’ theorem in 3- D
68
4 5 8
69
4 5 8 H E F G D C B A
70
4 5 8 H E F G D C B A
71
4 5 8 H E F G D C B A 5 4 E FG H EG 2 = 5 2 + 4 2 EG 2 = 25 + 16 EG 2 = 41 EG = 6.4 cm
72
Pythagoras’ theorem in 3- D 4 5 8 H E F G D C B A EG 2 = 5 2 + 4 2 EG 2 = 25 + 16 EG 2 = 41 EG = 6.4 cm A E G 8 6.4 AG 2 = 8 2 + 6.4 2 AG 2 = 64 + 41 AG 2 = 105 AG = 10.2 cm
73
Pythagoras’ theorem in 3- D 4 5 8 H E F G D C B A EG 2 = 5 2 + 4 2 EG 2 = 25 + 16 EG 2 = 41 EG = 6.4 cm A E G 8 6.4 AG 2 = 8 2 + 6.4 2 AG 2 = 64 + 41 AG 2 = 105 AG = 10.2 cm Note: 5 2 + 4 2 + 8 2 = 25 + 16 + 64 = 105
74
The equation of a circle
76
x 2 + y 2 = r 2
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.