1. Press Ctrl-A ©G Dear2008 – Not to be sold/Free to use Finding a Side Stage 6 - Year 12 General Mathematic (HSC)

2. 2 The Trigonometric Ratios (1/6) 45 o 13cm x h Cos 45 o = x 13 a ah Because we have a and h Cos we must use Cos. x13 13x x = 13 x Cos 45 o ≈ 9.192 388 ≈ 9.2cm

3. 3 3.1 The Trigonometric Ratios (2/6) 35 o 10m x h Sin 35 o = x 10 o oh Because we have o and h Sin we must use Sin. x10 10x x = 10 x Sin 35 o ≈ 5.735 764 ≈ 5.7m

4. 4 Finding an Unknown Side (3/6) 40 o 12m p a Tan 40 o = p 12 o oa Because we have o and a Tan we must use Tan. x12 12x p = 12 x Tan 40 o ≈ 10.069 195 ≈ 10.1m

5. 5 Finding an Unknown Side (4/6) 50 o 3m d h Sin 50 o = 3d3d o oh Because we have o and h Sin we must use Sin. x d d x d = 3 ÷ Sin 50 o ≈ 3.916 221 ≈ 3.9 m d x Sin 50 o = 3 ÷ Sin 50 o

6. 6 Finding an Unknown Side (5/6) 60 o 7m m a Cos 60 o = 7m7m h ah Because we have a and h Cos we must use Cos. x m m x m = 7 ÷ Cos 60 o ≈ 14.0 m m x Cos 60 o = 7 ÷ Cos 60 o

7. 7 Finding an Unknown Side (6/6) 60 o 10m w a Tan 60 o = 10 m o oa Because we have o and a Tan we must use Tan. x w w x w = 10 ÷ Tan 60 o ≈ 5.773 502 ≈ 5.8 m w x Tan 60 o = 10 ÷ Tan 60 o