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Published byDelphia Lester Modified over 9 years ago
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Types of Data: Ratio Specific intervals between consecutive numbers True zero value
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Interval level: Specific intervals between consecutive values Zero is just a number in the string
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Ordinal level: numbers establish rank order distance between numbers is not any specific interval e.g., 1st, 2nd, 3rd...
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Nominal level: Numbers only categorize data. Numbers have no mathematical value. e.g., 1 = male, 2 = female
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Chi Square Goodness of fit for nominal level data identifies if a sample of people conform to the categories as expected.
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Where: Chi Square Frequency expected Frequency observed
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Frequency expected: The amount of subjects that you would expect to find in each category based on known information.
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Frequency observed: The amount of subjects you actually find to be in each category in the present data.
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Let’s assume that: h.s. Some college MA Ph.D college 20% 25% 30% 15% 10%
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First: How many people do we expect to find in each category, based on these percentages? Assume that the sample that you test has n=50.
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The percentage needs to be written as a fraction or decimal.
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h.s. Some college MA Ph.D college 20% 25% 30% 15% 10%
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h.s. Some college MA Ph.D college 20% 25% 30% 15% 10%
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h.s. Some college MA Ph.D college 20% 25% 30% 15% 10%
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h.s. Some college MA Ph.D college 20% 25% 30% 15% 10%
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h.s. Some college MA Ph.D college 20% 25% 30% 15% 10%
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h.s. Some college MA Ph.D college 20% 25% 30% 15% 10% 10 12.5 15 7.5 5
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h.s. Some college MA Ph.D college 20% 25% 30% 15% 10% 10 12.5 15 7.5 5 5 7 25 12 1
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10 12.5 15 7.5 5 5 7 25 12 1 h.s. Some college MA Ph.D college
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10 12.5 15 7.5 5 5 7 25 12 1 h.s. Some college MA Ph.D college
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Some college: 1) 2) 3) 4)
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10 12.5 15 7.5 5 5 7 25 12 1 h.s. Some college MA Ph.D college
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1) 2) 3) 4) College:
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10 12.5 15 7.5 5 5 7 25 12 1 h.s. Some college MA Ph.D college
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M.A. 1) 2) 3) 4)
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10 12.5 15 7.5 5 5 7 25 12 1 h.s. Some college MA Ph.D college
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Ph.D. 1) 2) 3) 4)
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Critical Value: Chi Square table df = K-1 where k is # of groups df=4 crit value = 9.488
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17.49 > 9.48 Therefore there is a significant difference between the expected and observed frequencies.
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