1. Energy Changes & Phase Changes Heating & Cooling Curves

2. It takes energy to heat stuff up! For a pure substance in a single phase, we can calculate how much using Q = mC  T. –Q = energy in Joules –m = mass in grams –C = specific heat capacity –  T = change in temperature = T f - T i On the other hand, when something cools down, energy is released!

3. Q = mC  T C = specific heat capacity = amount of heat required to raise the temperature of 1 gram of a pure substance by 1  C. C is a physical constant. It is unique for every pure substance. Values of C are tabulated. C H2O = 4.2 J/g 

4. Heat Flow: hot to cold System – 1 phase 1 phase Environment

5. But what about phase changes? Sometimes more than one phase of a substance is present. For example, when melting ice, both liquid water and ice are present. Furthermore, the temperature is constant, so  T = 0, even though the beaker of ice water is absorbing heat from a hot plate.

6. All chemical & physical changes are accompanied by energy changes. Phase changes are physical changes. Sometimes energy is absorbed, sometimes energy is released. The energy change for a given phase change can be measured or calculated.

7. What are 6 possible phase changes and their names?

8. Potential Energy Energy of relative position. Molecules are always attracted to one another. You have to put energy into the system to pull molecules apart from one another. So the farther apart they are, the higher their potential energy.

9. Melting Ice Ice water on hot plate: ice is melting. The ice is absorbing heat from the hot plate and using it for the phase change. The temperature of ice-water mix is constant -- the heat energy from the hot plate is going into the phase change or potential energy of the system. The heat energy is not going to the kinetic energy. Remember, temperature is …

10. Identify a phase change as endothermic or exothermic. P.E. Solid Liquid Gas EndothermicExothermic Fusion Vaporization Sublimation Condensation Freezing Deposition

11. Heating & Cooling Curves 1 way to investigate energy changes. Measure temperature as a function of time at a constant heating or cooling rate.

12. Time Temperature I IIIIIIVV Solid Solid & Liquid Liquid Liquid & Gas Gas K.E.  K.E.↔ P.E.↔ P.E.  Melt pt. Boil pt.

13. Melting & Boiling Points Plateaus = Phase changes = Potential energy changes. Notice that as long as 2 phases are present, the temperature is constant. Melting point, Boiling point. Tiger

14. What happens to the temperature as heat is added at the boiling point? Nothing, until only 1 phase is present!

15. Heating Curve Tiger Graphic

16. To analyze a heating/cooling curve: Does the curve go uphill or downhill? Label the phases present in each region. Describe what happens to the K.E. in each region. Describe what happens to the P.E. in each region. Locate the melting point and boiling point.

17. Heating curve of H 2 O.

18. What is the melting point of this substance? The boiling point?

19. The heating rate is 150 J/min. If the substance takes 4 minutes to melt, how much heat energy was used to melt it? Experimental Approach

20. 3 equations for Q Q = mC  T Q = mH f Q = mH v Have to figure out which one to use for a given problem. Depends which section of heating curve. Look for hints in the problem.

21. Temperature Time Q = mH f Q = mH v Q = mC l  T Q = mC s  T Q = mC g  T

22. Q = mC  T: pure substance, single phase Temperature changed Temperature increased Temperature decreased Initial temperature Start temperature Final temperature Ending temperature From ____ to ____ Water

23. Q = mH f : liquid and solid present Ice Freezing Melting At 0  C (for H 2 O) At constant temperature

24. Heat of Fusion Amount of energy required to change 1 gram of a pure substance from a solid to a liquid at its melting point. Heat of Fusion = H f = physical constant. H f for water = 333.6 Joules per gram (Table B)

26. How much heat is absorbed when 10 grams of ice melts at 0 o C? Heat absorbed = mass of substance X heat of fusion of substance Q = mH f = (10 g)(333.6 J/g) = 3336 J Where does that energy go? Particles must overcome forces of attraction to move farther apart.

27. Q = mH v : liquid and gas present Steam Boiling Condensation or Condensing At 100  C (for H 2 O) At constant temperature

28. Heat of Vaporization Amount of energy required to convert 1 gram of a pure substance from a liquid to a gas at its boiling point. Heat of vaporization = H v = physical constant H v for water = 2259 J/g

29. How much energy does it take to vaporize 10 g of water? Q = mH v Q = (10 g)(2259 J/g) = 22590 J It takes a lot more energy to go from liquid to gas than from solid to liquid. Why?

30. The particles are spreading out a lot more!

31. Heats of fusion & vaporization Determined in calorimetry experiments.