1. Combustion analysis 4.40 g CO2 1 mol CO2 44 g CO2 1 mol C atoms 1 mol CO2 = 0.10 mol C atom 1.80 g H2O 1 mol H2O 18 g H2O 2 mol H atoms 1 mol H2O = 0.20 mol H atom 3.00g = weight O + weight C + weight H weight O = 3.00g - weight C weight H weight O = 3.00g – 12g/mol(0.1molC) – 1g/mol(0.2molH) = 1.60 g O 1 mol O atom 16 g O = 0.10 mol O atom

2. Combustion analysis (cont) Empirical formula: CH 2 O Original molecular weight: 180 g/mol Formula weight of CH 2 O: 30 g/mol 6 CH 2 O units required to get to formula weight. Thus the molecular formula is: C 6 H 12 O 6

3. Acetic Acid and Ethanol 4.20 g Acetic 1 mol acetic 60 g acetic 1 mol ester 1 mol acetic 88g ester 1 mol ester = 6.16g ester Total of 6.16 g of ethyl acetate can be made from this reaction

4. Iron(III) Oxide + Aluminum 152 g Fe 2 O 3 1 mol Fe 2 O 3 159.7 g Fe 2 O 3 2 mol Fe 1 mol Fe 2 O 3 55.84g Fe 1 mol Fe = 106 g Fe 74.2 g Al 1 mol Al 26.98 g Al 2 mol Fe 2 mol Al 55.84g Fe 1 mol Fe = 154 g Fe Thus the Fe 2 O 3 is the limiting reagent

5. Iron(III) Oxide + Aluminum 152 g Fe 2 O 3 1 mol Fe 2 O 3 159.7 g Fe 2 O 3 2 mol Al 1 mol Fe 2 O 3 26.98g Al 1 mol Al = 51.4 g Al Aluminum Remaining = Starting – Used Remaining = 74.2 g Al – 51.4 g Al = 22.8 g Al

6. Titanium(IV) Chloride 4.15 g TiO 2 1 mol TiO 2 79.9 g TiO 2 3 mol TiCl 4 3 mol TiO 2 189.7gTiCl 4 1 mol TiCl 4 = 9.82 g TiCl 4 5.67 g C 1 mol C 12.01 g C 3 mol TiCl 4 4 mol C = 67.2 g TiCl 4 Thus the Cl 2 is the limiting reagent. 6.78 g Cl 2 1 mol Cl 2 70.9 g Cl 2 3 mol TiCl 4 6 mol Cl 2 = 9.07 g TiCl 4 189.7gTiCl 4 1 mol TiCl 4 189.7gTiCl 4 1 mol TiCl 4