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Principal Stresses and Strain and Theories of Failure Strength of Materials Prof. A. S. PATIL Department of Mechanical Engineering Sinhgad Academy of Engineering, Pune
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6.2 NUMERICALS 2Strength of Materials06-12-2014
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2. The state of stress at a point in a strained material is shown in Fig. (i) Locate the principal planes and find the principal stresses, (ii) Locate the Max. shear stress planes and find the max. shear stress. Solution- A D C B 32 30 80 32 Stresses are in MPa Inclination of Principal planes θ P wrt Vertical : 4Strength of Materials06-12-2014
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Inclination of Max. shear stress planes θ S = θ P + 45 0. θ S = 14.09 0 + 45 0 = 59.09 0 &149.09 0. (wrt Vertical) Max. shear stress τ max : Principal stresses, σ P : 5Strength of Materials06-12-2014
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6 80 30 32 45 0 Strength of Materials06-12-2014
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3. Fig. shows the normal and tangential stresses on the two plane. Determine the principal stresses. Solution – Let the plane ED be at Ɵ with major principal plane. ……..i 7 45° E D F Strength of Materials06-12-2014
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8 ……….ii On plane EF, ……..iii Strength of Materials06-12-2014
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