1. Tuesday!!!!! 10/11/11 Bell Ringer 1)Get out your chapter pages, your practice problems, and paper to take notes. We are going over the Ch. 4 PPT and then we will discuss the practice problems. 2)Once you have annotated Chapter 4, pick up the practice problems packet and complete the following problems: 1)Review Questions: 1,3,4,5,6,9 2)Paired Exercises: 1,3,4,5,6,7,8,10,11,13,14,15,16,18,19, 20,22 3)Additional Exercises: 23, 24,25,27,30,32,34,36,40 4)Challenge Excersises: 42-45 Schedule 1.Bell Ringer 2.Ch. 4 PowerPoint 3.Practice Problems Don’t forget, you have until Tuesday to redo Exp. 3 and until Wednesday to retake the Unit 1 Test. HOMEWORK: Finish Practice Problems!! PAP Chemistry Teachers open the door, but you must enter by yourself. I CAN……solve chemistry problems by being an independent, creative thinker.

2. Chemical Equations Reactants → Products

3. Law of Conservation of Mass Mass of reactants = mass of products Mass is neither created nor destroyed

4. Law of Conservation of Energy Energy is neither created nor destroyed It may be transferred from one form to another

5. Energy Ability to do work PE – Stored energy – Energy due to an objects location – Gas: chemical potential energy KE – Energy in motion – Water in a dam is PE converted to KE

6. Heat Quantitative Measurement Measured in Joules (J) or Calories (cal) 4.184 J = 1 cal

7. Heat Capacity 1 cal or 4.184 J is the quantity of heat required to change the temp of 1 gram of water by 1°C Specific Heat: quantity of heat released or gained required to change the temp of the substance by 1°C. Specific heat of liquid water = 4.184 J/g°C…it is very high

8. Specific Heat Q = mcΔt – Q or q= heat in J or cal (can be negative or positive) – m = mass (grams) – c or C P or C R = specific heat in J/g°C or cal/g°C – Δt = change in temperature °C (final-initial) What is the specific heat of a substance that absorbs 2.5 x 10 3 joules of heat when a sample of 1.0 x 10 4 g of the substance increases in temperature from 10.0C to 70.0C? Q = 0.0042 J/g°C