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Do Now: #18 and 20 on p.466 Find the interval of convergence and the function of x represented by the given geometric series. This series will only converge when : Interval of convergence:
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Do Now: #18 and 20 on p.466 Find the interval of convergence and the function of x represented by the given geometric series. Sum of the series: So, this series represents the function Graphical support?
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Do Now: #18 and 20 on p.466 Find the interval of convergence and the function of x represented by the given geometric series. This series will only converge when : Interval of convergence:
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Do Now: #18 and 20 on p.466 Find the interval of convergence and the function of x represented by the given geometric series. Sum of the series: So, this series represents the function Graphical support?
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Section 9.1b
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Similar Problems: #42 and 44 on p.468 Find a power series to represent the given function and identify its interval of convergence. Compare to: Series: The series converges when : Interval of convergence:
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Similar Problems: #42 and 44 on p.468 Find a power series to represent the given function and identify its interval of convergence. Compare to: Series: The series converges when : Interval of convergence:
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Finding a Power Series by Differentiation Given that 1/(1 – x) is represented by the power series find a power series to represent Notice that this is the derivative of this !!! With the same interval of convergence: Graphical support?
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Theorem: Term-by-Term Differentiation If converges for, then the series obtained by differentiating the series for term by term, converges on the same interval and represents on that interval.
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Finding a Power Series by Integration Given that find the power series to represent With the same interval of convergence:
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Theorem: Term-by-Term Integration If converges for, then the series obtained by integrating the series for term by term, converges on the same interval and represents on that interval.
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Exploration 3 on p.465 1. 2. Since this function is its own derivative and takes on the value 1 at x = 0…. perhaps it is the exponential function? 3. 4.
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Exploration 3 on p.465 5. 6. 7. It appears that the first three partial sums may converge on (–1, 1)… The actual interval of convergence is all real numbers!!!
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